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Answer:
7.71 × 10⁻⁴ M/s
Explanation:
The initial rate of the reaction can be expressed by using the formula:
where the number of moles of O₂ =
where;
Pressue P = 1.00 atm
Volume V =5.74mL = (5.74 /1000) L
Rate R = 0.082 L atm/mol.K
Temperature = 298 K
= 2.35 × 10⁻⁴ mol
Δ[O₂] =
Δ[O₂] =
Δ[O₂] = 0.04626 M
The initial rate =
=
= 7.71 × 10⁻⁴ M/s