Answer:
11
Explanation:
Moles of KOH = 
Volume of water = 10 liters
Concentration of KOH is given by
![[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}](https://tex.z-dn.net/?f=%5BKOH%5D%3D%5Cdfrac%7B10%5E%7B-2%7D%7D%7B10%7D%5C%5C%5CRightarrow%20%5BKOH%5D%3D10%5E%7B-3%7D%5C%20%5Ctext%7BM%7D)
is strong base so we have the following relation
![[KOH]=[OH^{-}]=10^{-3}\ \text{M}](https://tex.z-dn.net/?f=%5BKOH%5D%3D%5BOH%5E%7B-%7D%5D%3D10%5E%7B-3%7D%5C%20%5Ctext%7BM%7D)
![pOH=-\log [OH^{-}]=-\log10^{-3}](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E%7B-%7D%5D%3D-%5Clog10%5E%7B-3%7D)

So, pH of the solution is 11
Answer:
D
Explanation:
A The calcium chloride dissolves in solution
B The mass of the solution totals 20 g
C The temperature of the solution is 35 degrees
D The solution became lighter in color
The correct answer would be that <u>the solution became lighter in color.</u>
An increase in temperature can also be considered a sign of a chemical reaction but in this case, the dissolution of calcium chloride in water is in itself exothermic.
A change in the mass of the final solution could also be considered a sign of a chemical reaction but in this case, the total mass equals the addition of the individual masses of the reactant.
The dissolution of calcium chloride in water is not enough as evidence of a chemical reaction. Dissolution can be a physical change of which, the evaporation of the water would retrieve the solute.
<em>A change in color, however, is one of the evidence to establish that a chemical reaction has occurred.</em>
The correct option is D.
The product will not be affected by the addition of twice as much Na₂CO₃.
<h3>What is Limiting reagent in stoichiometry ?</h3>
- The maximum quantity of the end product determined by a balanced chemical equation is known as the Stoichiometry.
- The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced, and the one which remains unconsumed after the final reaction is in Excess.
- Calculate the moles of each reactant present and contrast it with the mole ratio of the reactants in the balanced equation to determine which reactant is the limiting one.
Here,taking the stoichiometry into consideration, we find that the reaction happens with 1:1 ratio; so, adding twice the amount of Na₂CO₃ will lead to its excess making the other the limiting reactant, hence, it would not affect the yield of the product.
To know more about the Limiting reactant, refer to:
brainly.com/question/14222359
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