Question

Given:

Answer 1

Answer: 4.74 moles

Explanation:

$2LiBr+Ba\rightarrow BaBr_2+2Li$

Moles of Ba=$\frac{\text {given mass}}{\text {molar mass}}$

Moles of Ba=$\frac{325g}{137g/mol}=2.37 moles$

According to given balanced equation,

1 mole of Barium gives 2 moles of Li

Thus 2.37 moles of Barium gives=$\frac{2}{1}\times 2.37=4.74 moles$

Thus 4.74 moles of lithium will be produced by 135 g of barium.

Answer 2

4.73 mol for Edmentum users