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IRISSAK [1]
3 years ago
10

Assuming the relative rate of secondary hydrogen atom abstraction for the chlorination of propane is 3.9 times faster than the r

ate of primary hydrogen abstraction, calculate the relative amounts of propyl chloride and isopropyl chloride obtained in the free radical chlorination of propane. Based on the calculation what percentage of the mixture is expected to be 1−propylchloride?
Chemistry
1 answer:
Ghella [55]3 years ago
7 0

Answer:

% of n-propyl chloride = 43.48 %

Explanation:

There are 2 secondary hydrogens and 6 primary hydrogens

The rate of abstraction of seondary hydrogen = 3.9 X rate of abstraction of primary hydrogen

probability of formation of isopropyl chloride = 3.9 X 1 (relative rate X relative number of secondary hydrogens)

Probability of formation of n-propyl chloride = 1 X 3 (relative rate X relative number of primary hydrogens)

Total probability = 3.9

% of n-propyl chloride = 3 X 100 / 6.9 = 43.48 %

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yarga [219]
Hello!

The part of the carbon cycle where humans had the greatest impact is the return of CO₂ to the atmosphere by burning of ancient organic matter.

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Have a nice day!
4 0
3 years ago
the valence electrons of an atom of which element would feel a smaller effective nuclear charge than the valence electrons of a
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D. Strontium is the right answer
5 0
3 years ago
Heterocyclic aromatic compounds undergo electrophilic aromatic substitution in a similar fashion to that undergone by benzene wi
Readme [11.4K]

Answer:

See explanation

Explanation:

When we talk about electrophilic substitution, we are talking about a substitution reaction in which the attacking agent is an electrophile. The electrophile attacks an electron rich area of a compound during the reaction.

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8 0
3 years ago
When 0.49 g of a molecular compound was dissolved in 20.00 g of cyclohexane, the freezing point of the solution was lowered by 3
IRISSAK [1]

Answer: The molecular mass of this compound is 131 g/mol

Explanation:

Depression in freezing point:

\Delta T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

\Delta T_f = depression in freezing point  = 3.9^oC

k_f = freezing point constant  = 20.8^0C/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 0.49 g

w_1 = mass of solvent (cyclohexane) = 20.00 g

M_2 = molar mass of solute = ?

Now put all the given values in the above formula, we get:

(3.9)^oC=1\times (20.8^oC/m)\times \frac{(0.49g)\times 1000}{M_2\times (20.00g)}

M_2=131g/mol

Therefore, the molar mass of solute is 131 g/mol

7 0
2 years ago
Which of the following did you include?
natulia [17]

Answer:

The formula of ammonium fluoride is NH4F.

Explanation:

1 The atoms in each ion are bonded together covalently to form a single unit.

Wrong!

⇒ The atoms in an ion compound are linked together by an ionic bond.

2 The charge is distributed over the entire ion.

Wrong!

Ions have taken in or given up electrons. This happens in the atomic shell.

3 The formula of ammonium fluoride is NH4F.

Right!

4 The formula of potassium sulfate is K2SO

Wrong!

The formula for potassium sulfate is K2SO4.

5 0
3 years ago
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