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3 years ago

Question 12 (2 points)

Computers and Technology

2 answers:

Gelneren [198K]3 years ago

5 0

1.) narrative = a THATS all I can answer rn sorryyyy

Darina [25.2K]3 years ago

3 0

Emotins: a feeling that be positive, negative, or netural

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What an underlined word or phrase represents? (HTML AND CSS), has to be 9 letters long. kinda urgent

xz_007 [3.2K]

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3 years ago

Which expression correctly determines that String s1 comes before String s2 in lexicographical order

Assoli18 [71]

Options :

A.) s1 < s2

B.) s1 <= s2

C.) s1.compareTo(s2) == −1

D.) s2.compareTo(s1) < 0

E.) s1.compareTo(s2) < 0

Answer: E.) s1.compareTo(s2) < 0

Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.

If first string = s1 ; second string = s2

To compare s1 with s2, the format is ;

s1.compareTo(s2) ;

If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.

If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.

If both are s1 and s2 are the same, the output will be 0.

8 0

3 years ago

You have a group of friends coming to visit you for your high school reunion, and you want to take them out to eat at a local re

-BARSIC- [3]

Answer:

Python code is explained below

Explanation:

def RestaurentSelector():

#stroring the restaurants data

restaurents=[["Joe's Gourmet Burgers","no","no","yes"],["Main Street Pizza Company","yes","yes","yes"],["Corner Cafe","yes","no","yes"],["Mama's Fine Italian","yes","no","no"],["The Che'fs Kitchen","yes","yes","yes"]]

#taking the requirements for party

isVeg=input("Is anyone at your party a vegetarian? ")

isVegan=input("Is anyone at your party a vegan? ")

isGF=input("Is anyone at your party a gluten-free? ")

#printing the info

print("Hera are your restaurant choices :")

#loop to check each restaurent

for x in restaurents:

#checking for veg requirement

if isVeg=="yes" and x[1]=="no":

#skipping the current restaurent if is satisfying

continue

#checking for vegan requirement

if isVegan=="yes" and x[2]=="no":

#skipping the current restaurent if is satisfying

continue

#checking for glutan free requirement

if isGF=="yes" and x[3]=="no":

#skipping the current restaurent if is satisfying

continue

#if all requirementws are satisfied

#printing the restaurent name

print("\t",x[0])

#exiting the function\

#calling the function

RestaurentSelector()

4 0

3 years ago