The approximate volume of the model will be

<h3 /><h3>What is the approximate volume of the model? </h3>
It is given that


So the volume of the model will be =



Thus the approximate volume of the model will be 
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Answer:
(3,2)
Step-by-step explanation:
Let's solve this via elimination method:

By subtracting equation 2 from equation one we obtain:

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1. Let y=2 and so:

Therefore the solution for the system of equations is:
x=3 and y = 2 as an ordered pair we have (3,2)
Draw 40 boxes, and in a separate section draw another 40 boxes.
(If you have the time :) )
Answer: C
Step-by-step explanation: 5pi converts to 15.70796
Answer:
a =
Step-by-step explanation:
Given:
f(x) = log(x)
and,
f(kaa) = kf(a)
now applying the given function, we get
⇒ log(kaa) = k × log(a)
or
⇒ log(ka²) = k × log(a)
Now, we know the property of the log function that
log(AB) = log(A) + log(B)
and,
log(Aᵇ) = b × log(A)
Thus,
⇒ log(k) + log(a²) = k × log(a) (using log(AB) = log(A) + log(B) )
or
⇒ log(k) + 2log(a) = k × log(a) (using log(Aᵇ) = b × log(A) )
or
⇒ k × log(a) - 2log(a) = log(k)
or
⇒ log(a) × (k - 2) = log(k)
or
⇒ log(a) = (k - 2)⁻¹ × log(k)
or
⇒ log(a) =
(using log(Aᵇ) = b × log(A) )
taking anti-log both sides
⇒ a =