The volume of a sphere:

r - the radius
The diameter is twice the radius.
![d=36 \ in \\ r=\frac{36}{2} \ in = 18 \ in \\ \\ V=\frac{4}{3} \pi \times 18^3=\frac{4}{3}\pi \times 5832=\frac{23328}{3} \pi=7776\pi \ [in^3]](https://tex.z-dn.net/?f=d%3D36%20%5C%20in%20%5C%5C%0Ar%3D%5Cfrac%7B36%7D%7B2%7D%20%5C%20in%20%3D%2018%20%5C%20in%20%5C%5C%20%5C%5C%0AV%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%5Ctimes%2018%5E3%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%5Ctimes%205832%3D%5Cfrac%7B23328%7D%7B3%7D%20%5Cpi%3D7776%5Cpi%20%5C%20%5Bin%5E3%5D)
The exact volume of the sphere is 7776π in³.
Answer:
Option c. 11,488.21 cm3
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The volume of the sphere is equal to

we have
---> the radius is half the diameter

substitute


The answer to this one is W=-3/5 I think
Answer:
$117
Step-by-step explanation:
Given that:
They buy these books for $105 each and sell them to unsuspecting undergraduates at $222 each
Marginal Profit = Marginal Revenue – Marginal Cost.
Marginal Profit = $222 - $105
Marginal Profit = $117
the marginal profit for a single elementary statistics book $117
For the remaining unsold books in the middle of the semester he bundles them up and sells to vendor in another country for $40 each for which he suffers a marginal loss of $105 - $40 = $65 each