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galina1969 [7]
3 years ago
13

An item is regularly priced at $35. It is on sale for 20% off the regular price. How much (in dollars) is discounted from the re

gular price?
Mathematics
2 answers:
Lisa [10]3 years ago
4 0

Answer:

7

Step-by-step explanation:

you multiply 35 by .20

sukhopar [10]3 years ago
4 0
7 dollars I believe do 35 times 20%(.20) it equals 7 if you want the price for the item with the discount 35-7 (28)
You might be interested in
If 7 to the second power in parentheses to the X exponent equals 1 what is the value of x
sergey [27]
(7^2)^x = 1
49^x = 1

You should know that anything to the power of 0 is equal to 1, therefore x = 0.

49^0 = 1


Hope that helps :)
8 0
4 years ago
Expand and simplyfy (4x+3)(2x-5)
zheka24 [161]
(4x+3) (2x-5)
8x^2-20x+6x-15
8x^2-14x-15
7 0
3 years ago
There are 8,253 men and 10,327 women at a state university. If 43% of the men are in business and 27% of the women are in busine
fredd [130]

Answer:

68 students

Step-by-step explanation:

Number of men who major in business in the university= 0.43*8253=3548.79

Rounding off we have 3549 students

Number of women who major in business in the university= 0.27*10327=2788.29

Approximately 2789 students

Total students who major in Business= 3549+2789=6338 students

Total students in school= 8253+10327=18580

Probability of getting business major= 6338/18580

Out of 200 students, we expect

\frac {6338}{18580} \times 200=68.22389666

Approximately 68 students will be majoring in business

8 0
3 years ago
I need an answer to 2. a and b and 3. a
Katen [24]

The square of an odd number:

We're to conjecture, not do algebra, apparently.  1²=1, 3²=9, 5²=25, 7²=49, ...

We conjecture the square of an odd number is odd.

The product of two evens and an odd:

Again, we'll run some examples.

(2)(2)(1)=4

(2)(4)(3)=24

(4)(6)(5) =120

(4)(8)(1)=32

Conjecture: The product of two evens and an odd is a multiple of 4


Counterexample: The product of two fractions is never an integer

How about

3/4 × 4/3 = 1


4 0
4 years ago
A carpenter is building a rectangular room with a fixed perimeter of 300 ft. what dimensions would yield the maximum​ area?
Inessa05 [86]

Perimeter = 2(Length) + 2(Width)

300 = 2L + 2W → 150 = L + W → 150 - L = W

Area = Length · Width

A_{max} = L(150 - L) → A_{max} = 150L - L²

There are 2 different methods for solving (depending on which math course you are taking).

<u>Calculus</u>: find the derivative, set it equal to zero, and solve for L.

A_{max} = 150L - L² → 0 = 150 - 2L → 2L = 150 → L = 75

<u>Algebra</u>: find the vertex.

A_{max} = - L² + 150L → L = -b/2a → L = -150/2(-1) → L = 75

Once you solve for L, plug it into the Perimeter equation to solve for W:

150 - L = W → 150 - 75 = W → W = 75

Answer: 75ft x 75ft


3 0
4 years ago
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