The graphs below have the same shape. What is the equation of the blue

Taseem’s loose change consists of dimes and quarters. When you ask her how many of each type of coin she has, she gives you the

sweet-ann [11.9K]

The statement first, and the statement second are correct because the number of dimes is 34, and the number of quarters is 66

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

0.1x + 0.25y = 19.9 and

x + y = 100

Let x = number of dimes

y = number of quarters

After solving the above system of equations by substitution method.

$\rm \dfrac{398-5y}{2}+y=100$

y = 66

$\rm x=\dfrac{398-5\cdot \:66}{2}$

x = 34

Thus, the statement first, and the statement second are correct because the number of dimes is 34, and the number of quarters is 66

Learn more about the linear equation here:

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4 0

2 years ago

A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus

aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject $H_0: \mu= 1.6$ , we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis $H_0:\mu= 1.6$ (the null hypothesis always have the equal sign).

We have to test the null hypothesis

$H_0:\mu= 1.6$

The significance level for this test is 0.05

Calculation of the t-statistic:

$t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47$

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject $H_0: \mu= 1.6$ , we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0

3 years ago

Hey:) please help me on this one: Evaluate the function f(x) = 0.4x^2 - 3x - 8 for the value x = -2

Ksivusya [100]

Answer:

Step-by-step explanation:

8 0

4 years ago

In the figure below, angle y and angle x form vertical angles. Angle x forms a straight line with the 50° angle and the 40° angl

Nataly [62]

Step-by-step explanation:

sorry but u should provide with a diagram for better understanding of ur question

7 0

4 years ago

Which system of equations has a solution of approximately (–0.4, 1.1)?

BabaBlast [244]

Answer:

d

Step-by-step explanation:

6 0

4 years ago