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dem82 [27]
3 years ago
12

Three Linear Variables​

Mathematics
1 answer:
azamat3 years ago
8 0

Answer:

23 yellow, 30 pink and 12 blue balls

Step-by-step explanation:

Let the number of yellow, pink, blue, and black balls be y, p, b, and x respectively.

<em>From 1st sentence:</em>

y +p +b +x= 90

<em>"</em><em>60</em><em> </em><em>of</em><em> </em><em>them</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>pink</em><em>"</em><em> </em>

➜ y +b +x= 60

Given that 25 are black, x= 25.

<em>"</em><em>67</em><em> </em><em>of</em><em> </em><em>them</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>yellow"</em>

➜ p +b +x= 67

Subst. x= 25 into the above equations:

y +p +b +25= 90

y+ p +b= 65 -----(1)

y +b +25= 60

y +b= 35 -----(2)

p +b +25= 67

p +b= 42 -----(3)

I will rewrite the 3 equations for better clarity:

y +p +b= 65 -----(1)

y +b= 35 -----(2)

p +b= 42 -----(3)

(1) -(2):

p= 65 -35

p= 30

(1) -(3):

y= 65 -42

y= 23

Substitute p= 30 and y= 23 into (1):

23 +30 +b= 65

b= 65 -53

b= 12

Thus, there 23, 30 and 12 yellow, pink and blue balls respectively.

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