Answer:
4x^2(3+4x)
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
Answer:
Step-by-step explanation:
In order to do this we need to isolate y by performing the inverse operations on the other values like so...
a) 10x + 5y = 20 ... subtract 10x on both sides
5y = 20 - 10x ... divide both sides by 5
y = 4 - 2x ... we can move the 2x to the right to make it into y = mx + b
y = -2x + 4
b) 3x - 2y = 10 + 4x ... subtract 3x on both sides
-2y = 10 + x ... divide both sides by -2
y = -5 - 0.5x ... move -0.5 to the left so it matches y = mx + b
y = -0.5x - 5
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
The first parabola has vertex (-1, 0) and y-intercept (0, 1).
We plug these values into the given vertex form equation of a parabola:
y - k = a(x - h)^2 becomes
y - 0 = a(x + 1)^2
Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:
1 = a(0 + 1)^2, and from this we know that a = 1. Thus, the equation of the first parabola is
y = (x + 1)^2
Second parabola: We follow essentially the same approach. Identify the vertex and the two horizontal intercepts. They are:
vertex: (1, 4)
x-intercepts: (-1, 0) and (3, 0)
Subbing these values into y - k = a(x - h)^2, we obtain:
0 - 4 = a(3 - 1)^2, or
-4 = a(2)². This yields a = -1.
Then the desired equation of the parabola is
y - 4 = -(x - 1)^2