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3 years ago

How many chromosomes does an individual with Turner syndrome have? (A)4n (B)2n + 1 (C)n + 1 (D)n – 1 (E)2n – 1

1 answer:

8 0

In your question that ask to find out or to select which of the following among your choices does and individual with a Turner Syndrome and we all know that this is one of the disease that has a chromosomal descripancies and the answer is B. 2n-1

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A reasonable speed for a snail is _____.

lisabon 2012 [21]

A, the others are unrealistic speeds.

4 0

4 years ago

Which type(s) of cell division (mitosis, meiosis l, meiosis Il) reduce(s) the chromosome number by half? Which type(s) of cell d

PSYCHO15rus [73]

Answer:

Which type(s) of cell division reduce(s) the chromosome number by half?

Meiosis l

Which type(s) of cell division can be classified as reductional?

Meiosis I

Which type(s) of cell division can be classified as equational?

Mitosis and Meiosis II

Explanation:

Meiosis is a type of cell division which occurs in the germ or reproductive cells to produce gametes. It is completed in the two stages, meiosis I and meiosis II. The cells which are going to divide by meiosis are diploid having two sets of chromosomes. Meiosis I is the first stage of the meiosis. At the end of meiosis I two daughter cells are formed having only 1 set of chromosomes and chromosome numbers are reduced to half. Thus, meiosis I is a reductional division.

Mitosis and meiosis II is the equational division as after division chromosome number remains the same as in the parent.

6 0

4 years ago

How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C

fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios) for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3' NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3' NO STOP CODON

5'... CTT ACA GTT TAT TGA TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG TAA G

4)Now you need to find start (AGT in terms of DNA) and stop codons(TAA, TAG, TGA, also in terms of DNA), in 5->3 and de reverse complementary.

As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

8 0

3 years ago

Pre-leukemia myelodysplastic features in acute myeloid leukemia may include.

Alona [7]

Answer:

B) Hypogranular neutrophils

Explanation:

Myelodysplastic syndrome occurs due to a disordered production of blood cells in the bone marrow that die before they are even released into the bloodstream. This syndrome is of great clinical significance as they may progress to Acute Myeloid Leukemia. Generally, when this disease has pre-leukemic features it may include hypogranular neutrophils which is one is a feature of neutrophil dysplasia commonly observed in myelodysplastic syndromes.

6 0

3 years ago

What is a benefit of using bioenergy over nuclear energy?

Dmitry [639]

Answer:

O Bioenergy does not release harmful greenhouse gasses.

Explanation:

Nuclear energy might not releases as much greenhouse gasses as fossil fuels do but it still releases some. Bioenergy produces energy by using 100% natural elements whereas nuclear energy does not.

6 0

2 years ago