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goldfiish [28.3K]
3 years ago
11

Find the simple interest on a P10500 loan at 20% for two years. (show

Mathematics
1 answer:
Anni [7]3 years ago
6 0

Answer:

P4200

Step-by-step explanation:

SI=PRT/100

P=Principal which is P10500

R=Rate which is 20%

T=Time which is 2 years

So SI= 10500×20×2/100

=P4200

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The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
posledela

Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

t is the time elapsed

p is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

N(t) = 74g * (\frac{1}{2})^{t/2.8days

b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

7 0
1 year ago
Can someone explain how to calculate a unit rate ​
MArishka [77]

Answer:

It's like 60 miles per (1) hour or 20 mL per (1) second. Independent value has to equal 1.

5 0
2 years ago
Helpppppppppppppppppppp
a_sh-v [17]
In order going down:
5 3/5
6 5/6
4 2/3
10 1/3
11 2/3
3 0
3 years ago
This is part 1. Please help
ahrayia [7]
For the first one you would do:
X rad 3=7 divide by rad 3 in both sides and you don’t wanna leave a radical in the denominator so multiply rad 3 in both denom. And numerator and then you get 7rad3/3.

A 30:60:90 triangle always have n:2n:n rad 3 so since 2n=10 you would get n=5 and since BC is n rad3 so you would get 5rad 3.

In a 45:45:90 triangle it is n:n:n rad 2, since AC=3 then AB= 3 and then BC= 3 rad 2

Since AC and AB are congruent you they both would be 12 so it is true.

6 0
2 years ago
I need this answer plzzz!!
Dmitriy789 [7]

Answer: True, False, False, False, False

<u>Step-by-step explanation:</u>

a) 5x - 7(x - 1)

   5x - 7x + 7

         -2x + 7   ⇒  a = -2, b = 7   <em>One Solution</em>

b) 3(x - 5) - 7

   3x - 15 - 7

       3x - 22   ⇒  a = 3, b = -22   <em>One Solution</em>

c) 2 - 7x + 3 + 4x

  4x - 7x + 3 + 2  

              -3x + 5  ⇒   a = -3, b = 5   <em>One Solution</em>    

d) -3(x - 3) - 1

   -3x + 9 - 1

       -3x + 8   ⇒   a = -3, b = 8   <em>One Solution</em>

e) -5x + 2 + 2x + 4

   -5x + 2x + 2 + 4

                  -3x + 6  ⇒   a = -3, b = 6   <em>One Solution</em>  

4 0
3 years ago
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