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2 years ago

Just need some help with this question.

1 answer:

n200080 [17]2 years ago

3 0

The rate of each train of the northbound train traveled 10 miles per hour faster than the southbound train 26 miles per hour.

<h3>what is speed?</h3>

Speed is the time rate at which an object is moving along a path

Let the speed of southbound train is x miles/hour

so, northbound train has speed of x+10 miles/hour.

then, Speed of both train = Total distance/ total time

(x+10+x)=210/5

2x+10= 210/5

2x+10= 42

2x= 32

x= 16 miles per hour (southbound train)

northbound train: 16+10=26 miles per hour

Learn more about this concept here:

brainly.com/question/15544987

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The temperature one winter morning is -8 °f define

AnnZ [28]

Umm its cold out. the temperature is -8. what are you asking?

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4 years ago

Is it possible for the function f(x) - 5 x 2^x to have an output of 200?

Advocard [28]

Answer:

The solution is possible

Step-by-step explanation:

Given

$f(x) = 5 * 2^x$

Required

Is an output of 200, possible?

To know if it is possible or not, we start by substituting 200 for f(x)

$200 = 5 * 2^x$

Divide both sides by 5

$\frac{200}{5} = \frac{5}{5} * 2^x$

$\frac{200}{5} = 2^x$

$40 = 2^x$

$2^x =40$

Take logarithm of both sides

$log2^x =log40$

Apply law of logarithm

$xlog2 =log40$

Divide both sides by log2

$x = \frac{log40}{log2}$

$x = \frac{1.6021}{0.3010}$

$x = 5.32$

for f(x) = 200, x is approximately 5.32

Hence, the solution is possible

8 0

3 years ago

Y=-2 y=3x+1 in graph

Airida [17]

Answer:

The solution of the system is x=-1, y=-2

Step-by-step explanation:

we have

$y=-2$ ----> equation A

$y=3x+1$ ----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both lines

using a graphing tool

The intersection point is (-1,-2)

see the attached figure

therefore

The solution of the system is x=-1, y=-2

3 0

3 years ago

Are the two lines 3x - 4=-7 and x + 3y=6 parallel?

IceJOKER [234]

Answer:

No because the slopes arent the same (I’m guess it was -4y and not -4)

Step-by-step explanation:

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4 years ago

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Find the cosine of ∠J.

Lelu [443]

Answer:

$\cos = \frac{base}{hypotenuse} = \\ \cos(j) = \frac{ \sqrt{29} }{ \sqrt{94} } = \sqrt{ \frac{29}{94} } \\ answer = \sqrt{ \frac{29}{94} }$

4 0

3 years ago