Answer:
hypotenuse is the correct answer
Answer:
the answer is
t + u = 9
10t + u = 10u + t – 9
Step-by-step explanation:
Answer:
a) 0.06
b) 0.778
Step-by-step explanation:
Let's suppose a community of 100 families just to facilitate the calculation.
30% of the families own a dog
Dog = 30% of 100 = 30
20% of the families that own a dog also own a cat = 20% of 30 = 6
27% of all the families own a cat = 27% of 100 = 27
So, 6 families own a dog and a cat.
As 30 families own a dog, [30 - 6 =] 24 families own only dogs
As 27 families own a cat, [27 - 6 = ] 21 families own only cats
See picture attached.
a) What is the probability that a randomly selected family owns both a dog and a cat?
P(dog and cat) = dog ∩ cat/total = 6/100 = 0.06
b) What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
So, only cat/total cat
P (not dog|cat) = 21/27 = 0.778
Answer:
<h3>30 tiles need to buy for same cost in both store.</h3>
Step-by-step explanation:
Let x be the number of tiles to buy for same cost in both store.
18+0.69 · n = 1.29 · n,
1.29n -0.69n =18 or
0.6n =18
n =18/0.6=30
Therefore, 30 tiles need to buy for same cost in both store.[Ans]
I believe this means y=13
