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Mazyrski [523]
2 years ago
6

There are 6 orange marbles, 2 red marbles, 3 white marbles, and 4 green marbles in a bag. Once a marble is drawn, it IS replaced

. Find the probability of selecting 2 orange marbles in a row P(orange, orange). Write your answer as a simplified fraction
Mathematics
1 answer:
professor190 [17]2 years ago
4 0

The probability of selecting two orange marbles with replacement is 36/169.

Data;

  • Orange= 6
  • Red = 2
  • Green = 4

<h3>Probability with replacement</h3>

Since after each draw, the orange marble is replaced.

The total number of marbles in the bag is

6+3+4 = 13

And the number of orange marbles is 6.

For the first selection, the probability of selecting one orange is

P = \frac{6}{13}

After drawn and replaced, the probability of selecting another marble is

P = \frac{6}{13}

And the probability of selecting two orange marbles with replacement is

P = \frac{6}{13} * \frac{6}{13} = \frac{36}{169}

The probability of selecting two orange marbles with replacement is 36/169.

Learn more on probability here;

brainly.com/question/24756209

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The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0
3 years ago
Please help me on this question.
Kay [80]

Answer:

3×(27-7) says to subtract 7 from 27 first, then multiply with 3; but 3×27-7 says to multiply 3 by 27 first ,then subtract 7.

The second bullet is the correct option

7 0
3 years ago
Best explained and correct answer gets brainliest.
kipiarov [429]

total = 2372* (1+0.045)^20=

2372*1.045^20=

2372 * 2.411714025= 5720.585

she will have 5720.59 in 20 years

6 0
3 years ago
Two of your friends, Matt and Karen, both run to you to settle a dispute. They were working on a math problem, and got different
Anna11 [10]
So in matt's equation, he made a mistake in the a transision from line 2 to line 3 
in line 2:  -4(-2)2
in line 3: -4(4) 
the mistake is that -2 times 2 is not equal +4 it is equal to -4
also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5

so he first subtracted 10 then divided, he should have divided then subtracted
so the equation should have equaled 

Karen used the correct (-) times (+) property and the order of operations
so Karen is correct and Matt is wrong.

5 0
3 years ago
Read 2 more answers
Find the x-intercepts of the parabola with vertex (-3,-18) and y-intercept at (0,0)
statuscvo [17]
Y + 18 = a(x + 3)^2 
<span>0 + 18 = a(0 + 3)^2 </span>
<span>18 = 9a </span>
<span>2 = a 
</span>
<span>y = 2(x + 3)^2 - 18 </span>
<span>0 = 2(x + 3)^2 - 18 </span>
<span>18 = 2(x + 3)^2 </span>
<span>9 = (x + 3)^2 </span>
<span>± 3 = x + 3 </span>
<span>-3 ± 3 = x </span>
<span>x = 0 or -6 
</span>
<span>(0, 0) and (-6, 0)</span>
5 0
3 years ago
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