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Zinaida [17]
3 years ago
5

In which quadrant does the point (-5, 0) lie?

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

you need to send a pic but gnerally in quadrant 1

Step-by-step explanation:

ELEN [110]3 years ago
6 0
A. Quadrant I
this is where it should be
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3 years ago
Cuanto valen 75 sobres a $2,000 el cien?
sergey [27]
<span>Igual que el último.
Si es "$ 2,000 por 100 sobres, dividiremos 2,000 / 100 y obtendremos 20, luego multiplicaremos 20 por 75 y obtendremos" $ 1500 ".
 
Esta es la ecuación
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7 0
3 years ago
HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x
Anna35 [415]

 

\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0


\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}




3 0
3 years ago
PLEASE HELP ME WITH BOTH OF THESE PROBLEMS THIS IS DUE SOON PLEASE HELP ME
iogann1982 [59]

Answer:

Step-by-step explanation:

4.

a)

P = 2width + 2length

8x = 2x + 2 length; 8x-2x = 2 length; 6x=2 length

length = 3x

b)

sides= 1/4 of 3x = 3x/4

perimeter of square = 4* side = 4*3x/4 = 3x

c)

x= 4

P rectangle =8x= 8*4= 32

P square = 3x = 3*4 = 12

32-12 = 20 cm greater is the P rectangle than P of square

d)

A rectangle = 2x*x = 2*4*4 = 32

A square =(3x/4)² = (3*4/4)² = 9

32-9 = 23 cm² greater is the A rectangle than A of square

5.

4Comic+1 Nonfiction

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1 nonfiction = (3+7y)+ 2y

a)

1 nonfiction = 7y+2y+3 = 9y+3

b)

total= 8y+9y+3 = 17y+3

if y=4

total = 17*4 +3  = $71

7 0
3 years ago
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