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2 years ago

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I am stressed, I need help with assignments, but nobody knows how to do them....if you want to try to, go to my recent questions

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1 answer:

aksik [14]2 years ago

8 0

I’m sorry, but how do I see you’re recent questions? I’d love to help! However I have no clue how to find the questions.

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The following table lists the masses, in grams, of the nine planets (including dwarf planet Pluto). Use the data to choose the c

Marrrta [24]

The ratio between the masses of Jupiter and Venus is

$\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}$

We can separate the coefficient and the powers of ten:

$\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}=\dfrac{1.989}{4.869}\cdot \dfrac{10^{30}}{10^{27}}$

Use the exponent rule

$\dfrac{a^b}{a^c}=a^{b-c}$

to simplify the powers of 10:

$\dfrac{10^{30}}{10^{27}}=10^3$

So, the ratio is

$\dfrac{1.989}{4.869}\cdot 10^3\approx 0.4\cdot 10^3=400$

So, Jupiter has a mass that is approximately 400 times greater than Venus's.

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3 years ago

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Tanya [424]

The median is 42, the lower is 36, and the upper is 86

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2 years ago

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F(x)= 4x^3-8x-2x^6 in standard form

tankabanditka [31]

ANSWER-

2x(2x^2-4-x^5)

EXPLANATION-

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2 years ago

What is the approximate area of the shaded region?

vladimir2022 [97]

The answer is 13.76 meters squared.

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3 years ago

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Simplify.<br><br> −3+80÷8−5⋅(−1) plz help

Sliva [168]

Answer:

18

Step-by-step explanation:

-3 + 80 ÷ 8 -5 · (-1) ⇒ -3 + 10 + 5 ⇒ 18

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