Répondre:
r <27
Explication étape par étape:
Compte tenu de l'inégalité 5r + 9> 10r - 126
Nous devons trouver l'ensemble de solutions
5r + 9> 10r - 126
Ajouter 126 des deux côtés
5r + 9 + 126> 10r - 126 + 126
5r + 135> 10r
5r-10r> -135
-5r> -135
Divisez les deux côtés par -5 (notez que le signe changera)
-5r / -6 <-135 / -5
r <27
Par conséquent, les ensembles de solutions sont des valeurs inférieures à 27
Answer:
See explanation
Step-by-step explanation:
Plot the solution sets to both inequalities.
1. For the inequality
First, plot the dotted line
(dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

so the origin does not belong to the needed part. Shade the part, which does not include origin.
2. For the inequality
First, plot the dotted line
(dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

so the origin does not belong to the needed part. Shade the part, which does not include origin.
3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.
Answer:
- Least Value = 2
- Median = 6
- Greatest Value = 10
- Third Quartile = 8
- Range = 8 (10 - 2 = 8)
- First Quartile = 5
Step-by-step explanation:
Arc Length is 1/4th of the circumference .
<u>Step-by-step explanation:</u>
Here we need to find fraction of the circumference is this arc when An arc subtends a central angle measuring
radians ! Let's find out :
We know that circumference of an arc subtending a central angle of x is :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , Arc Length is 1/4th of the circumference .
Answer:
1. SSS
2. Q and S
3. 20
Step-by-step explanation:
1. SSS similarity: If the corresponding sides of two triangles are proportional, then the two triangles are similar.
Triangles NLM and WUV are similar by SSS similarity, because

2. Completed steps:
a) draw a circle with center at P and radius r
b) draw a circle with center at Q and radius r
c) using compass, measure the distance between two points of intersection of the first circle with angle rays
d) using point of intersection of the second circle with PQ as a center, draw the circle of radius equal to the distance from c) to get point S
Last step: connect points Q and S, line QS will be parallel to line r.
3. If lines MN and UT are parallel, then angles MUT and VMN are congruent; also angles UTN and MNV are congruent.
AA similarity: In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar .
By AA similarity, triangles VMN and VUT are similar, thus
