<span>a) Expressa o custo mensal C como uma função da kilometragem percorrida x, assumindo que uma relação linear descreve bem o problema.</span>
What’s the full question?
Answer:
Basically it's asking for the sum of 212 + 216 + 220 + ..... 586
Each number is 22 more than the previous one.
Therefore the sum will be 212 + (212+22) + (212+22*2) + (212+22*3)
the amount of numbers from 212 through 586 is 18.
Therefore we will need 212 plus 212 * 17 = 3,816 *******************
We will also need all those 22's.
We must add 22 *1 plus 22*2 plus 22*3 ..... plus 22*17
Which equals 22 + 44 + 66 + 88 ... 374
Which totals 3,366 *****************
So, we total 3,816 + 3,366 which equals 7,182
Step-by-step explanation:
= 6+10p because you just take out the numbers and you can't do anything with the 10p
P(TeamA) = 0,43
P(Female) = 0,52
P(TeamA and Female) = 0,19
P(TeamA or Female) = ?
P(TeamA or Female) = P(TeamA) + P(Female) - P(TeamA and Female) <=>
P(TeamA or Female) = 0,43 + 0,52 - 0,19 <=>
P(TeamA or Female) = 0,76 or 76%