Ask question

Ask question

All categories

2 years ago

10

What do the graphs of multiplicative patterns have in common?

1 answer:

alukav5142 [94]2 years ago

7 0

They repeat by adding that same number again and again

You might be interested in

Write a quadratic function with two real zeros.

satela [25.4K]

The formula for quadratic equation is given by:

x² - (sum)x + (product) = 0

so if we have real roots of 3 and 5

<span> x² - (3 + 5)x + (3*5) = 0
</span> x² - 8<span>x + 15 = 0
</span>
so if we have real roots of -3 and -6

<span> x² - (-3 - 6)x + (-2*-6) = 0
</span> x² - (-9<span>x) + 12 = 0
</span> x² + 9<span>x + 12 = 0</span>

5 0

3 years ago

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

3 0

2 years ago

Write the equations of the line

Basile [38]

Look at the picture it explains the answer

5 0

2 years ago

CAN SOMEONE PLEASE HELP ME!!! I’ll mark brainliest

Grace [21]

Answer:

im pretty sure its the 3rd one

5 0

2 years ago

Read 2 more answers

Enter an inequality that represents the graph in the box.

ANTONII [103]

The inequality that represents the graph in the box is

$y>-3x+6$

Given :

The graph of the linear inequality

Lets pick two points from the graph to frame the linear equation

Slope intercept form of the equation is

$y=mx+b$

Where m is the slope and b is the y intercept

y intercept is (0,6) from the graph

so b=6

Now we find out slope m using formula

Pick two points (0,6) and (2,0)

$slope = \frac{y_2-y_1}{x_2-x_1} \\m=\frac{0-6}{2-0} =-3$

m=-3

So the equation is $y=-3x+6$

Now we check the inequality sign by testing any point on shaded area

lets pick (4,0)

lets plug in 4 for x and 0 for y

$y=-3x+6\\0=-3(4)+6\\\\0=-6\\0>-6$

The inequality for the given graph is

$y>-3x+6$

we cannot use >= sign because we have dotted lines

Learn more : brainly.com/question/17203372

5 0

2 years ago