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3 years ago

What do the graphs of multiplicative patterns have in common?

Mathematics

1 answer:

alukav5142 [94]3 years ago

7 0

They repeat by adding that same number again and again

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Can anyone help me with my math test heres another question on it!!

Sliva [168]

Answer: A

Step-by-step explanation:

Area= Base x Height

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3 years ago

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Find the range of f(x)=-2x-5 for domain -2, -1, 1, 2

SashulF [63]

Range = {-2(-2) - 5, -2(-1) - 5, -2(1) - 5, -2(2) - 5} = {4 - 5, 2 - 5, -2 - 5, -4 - 5} = (-1, -3, -7, -9}

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3 years ago

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If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

2 years ago

Wouldn't this be true ?

Lana71 [14]

I think this is true

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3 years ago

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Arnie's car used 100 cups of gasoline during a drive.He paid $3.12 per gallon of gas.How much did the gas cost?

Elan Coil [88]

There are 16 cups in a gallon. Divide 100 into 16 to get 6.25. You now just multiply 3.12 by 6.25 to get 19.5. Your answer is $19.50. Hope this helps!

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3 years ago