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olga_2 [115]
3 years ago
6

1E. The number 2A5A0A2 is divisible by 99. What is the digit A?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

We know, a number is divisible by 9 if the sum of digits is also divisible by 9.

Also, since A is an digit, so A is in between 0 to 9.

2+A+5+A+0+A+2  = 3A + 9

3A + 9 should be divisible by 9.

3A + 9 = 9n

A = (9n -9)/3

For n= 1 :

A = 0

For n=2 :

A = 3

For n= 3 :

A = 9

After this A > 9 which is not accepted.

Therefore, the digit A can be 0, 3 and 9 .

Hence, this is the required solution.

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I don’t know how to find the LCM for this.
nekit [7.7K]

Answer:

B

Step-by-step explanation:

7mn³|7m²n³ ---14mn^5

       | m---2n²

LCM=7mn³×m×2n²

=14m²n^5

or LCM of 7,14 =14

Highest power of m=2

Highest power of n=5

LCM=14m²n^5

6 0
3 years ago
Match the phenomenal expression on the left with the simplified version on the right
nalin [4]

Given the polynomial expression:

(y + 5)²

(y - 5)(y + 5)

Let's simplify each of the given expression:

a.) (y + 5)²

The given equation is a factor of a perfect square trinomial. For this type of expression, the following is the formula for expanding it.

\text{ (a+b)}^2\text{ = }a^2\text{ + 2ab + }b^2

We get,

\mleft(y+5\mright)^2=(y)^2+2(y)(5)+(5)^2(y+5)^2=y^2+10y+25

b.) (y - 5)(y + 5)

To be able to simplify the following expression. We will be using the formula for the difference of two squares.

(a+b)(a-b)=a^2-b^2

We get,

\mleft(y-5\mright)\mleft(y+5\mright)=(y)^2-(5)^2(y-5)(y+5)=y^2-25^{}

8 0
1 year ago
Please show your work<br> What is the solution of the equation <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%2B13%7D%20-5%3D
Hatshy [7]
Add the five to each side.
then square it to get rid of the square root
2x+13=(5+x)^2
2x+13=x^2+10x+25
2x=x^2+10x+12
x^2+8x+12=0
(x+6)(x+2)
x+6=0
x+2=0
answers are -2 and -6, however, when pluging -6 in it doesnt work, so it is only -2.
3 0
3 years ago
Solve for x. 3x + 5 = 23​
Lunna [17]

[|] Answer [|]

\boxed{X \ = \ 6}

[|] Explanation [|]

3x + 5 = 23

_________

_________

Subtract 5 From Both Sides:

3x + 5 - 5 = 23 - 5

Simplify:

3x = 18

Divide Both Sides By 3:

\frac{3x}{3} \ = \ \frac{18}{3}

Simplify:

X = 6

_________

_________

- Check Your Work -

Substitute 6 For X:

3 * 6 + 5 = 23

Parenthesis

Exponents

Multiply

Divide

Add

Subtract

3 * 6 = 18

18 + 5 = 23

\boxed{[|] \ Eclipsed \ [|]}

8 0
3 years ago
Read 2 more answers
Please answer this question​
Y_Kistochka [10]

\bold{\huge{\underline{ Solution }}}

<u>Before </u><u>answering </u><u>the </u><u>given </u><u>question</u><u>, </u><u>you </u><u>should </u><u>know </u><u>the </u><u>difference </u><u>between </u><u>polygon </u><u>and </u><u>regular </u><u>polygon</u><u>. </u>

  • Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
  • Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

<u>There </u><u>are </u><u>different </u><u>types </u><u>of </u><u>polygon </u><u>based </u><u>on </u><u>the </u><u>sides </u><u>:</u><u>-</u>

  • A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

I have thought to make a 4 side polygon that is quadrilateral.

<u>Steps </u><u>of </u><u>construction </u><u>:</u><u>-</u><u> </u>

  • Step - 1 :- Draw a 5 cm line AB horizontally
  • Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
  • Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
  • Step - 4 :- Now, join the line AD
  • Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.

<u>Result </u><u>:</u><u>-</u><u> </u> All the angles are equal that is 90° each.

<u>Conclusion </u><u>:</u><u>-</u><u> </u> The above figure is square as it is having equal sides and angles.

<h3><u>Now</u><u>, </u><u>we </u><u>have </u><u>to </u><u>find </u><u>the </u><u>sum </u><u>of </u><u>the</u><u> </u><u>angles</u><u> </u><u>of </u><u>the </u><u>polygon </u><u>:</u><u>-</u></h3>

<u>Here</u><u>, </u><u> </u>

  • All angles are equal in measure 90°

<u>Therefore</u><u>, </u>

The sum of the angles of the given polygon

\sf{ = 90{\degree} + 90{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 180{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 270{\degree} + 90{\degree} }

\sf{ = 360{\degree} }

Hence, The sum of the angles of the above polygon is 360° .

6 0
2 years ago
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