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jok3333 [9.3K]
3 years ago
15

When ordering a student desk priced at $69.00, the shipping charges are 6%. What is the total cost of the desk?

Mathematics
2 answers:
Wittaler [7]3 years ago
7 0
Since the desk is $69.00 and the shipping charges are 6%

69*.06= 4.14

Your tax would be $4.14 so,

$4.14+$69.00= A total of $73.14
goldenfox [79]3 years ago
3 0
Shipping charges = 6% x $69 = 0.06 x 69 = $4.14

Total cost = $69 + $4.14 = $73.14

Answer: $73.14
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1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

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As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

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Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

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Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

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a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

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