X+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10+x+11+x+12/12
12x+78/12 = 132 times 12 is
12x+78 = 1,548 minus 78
12x = 1,506 divide by 12
x = 125.5 I believe is the answer, sorry if it is wrong
Answer:
13 cm × 12 cm
Step-by-step explanation:
The diagonal of the top or bottom faces of the box is the hypotenuse of a triangle with legs 12 cm and 5 cm. The Pythagorean theorem tells you that diagonal length is ...
d = √(12² +5²) = √(144 +25) = √169 = 13 . . . cm
The width of the divider is 13 cm.
The height of the divider is shown as 12 cm.
The dimensions of the dividing rectangle are 13 cm by 12 cm.
Differentiate the given solution:

Now, given that <em>x</em> (<em>π</em>/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have



Similarly, given that <em>x'</em> (<em>p</em>/4) = 0, you have



From this result, it follows that

So the particular solution to the DE that satisfies the given conditions is

Answer:
hexagonal pyramid
Step-by-step explanation:
i think its this but otherwise pay attention in class