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3 years ago

Plz help me its the last question

Chemistry

1 answer:

svetoff [14.1K]3 years ago

3 0

Answer:

¹⁶⁸₇₉Au

Explanation:

The symbol of the atom is given as;

¹⁷²₈₁Tl

If undergoes a nuclear reaction and it ejects an alpha particle;

An alpha particle is the same as an helium atom

¹⁷²₈₁Tl → ₂⁴H + ₐᵇK

K is the hypothetical symbol of the new atom

b is the new mass number

a is the new atomic number;

Conserving mass number;

172 = 4 + b

b = 172 - 4 = 168

Conserving atomic number;

81 = 2 + a

81 - 2 = a

a = 79

The new compound is gold with a symbol of;

¹⁶⁸₇₉Au

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$\boxed{\text{ B. Increase the temperature and decrease the pressure.}}$

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Let's say the reaction is

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I like to consider heat as if it were a reactant or a product in a chemical equilibrium.

Another way to write the equilibrium would be

heat + R ⇌ 2P

According to Le Châtelier's Principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

Let's consider each of the stresses in turn.

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3 years ago

If Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?

Fiesta28 [93]

The given sentence is part of a longer question.

I found this question with the same sentence. So, I will help you using this question:

For the reaction N2O4(g) ⇄ 2NO2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm). If Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?

(a) Q = K; The reaction is at equilibrium.
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(c) Q > K; The reaction will proceed to the left.

The answer is the option (c) Q > K; The reaction will proceed to the left, since Qp = 1, and 1 > 0.15.
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Kp is the equilibrium constant in term of the partial pressures of the gases.

Q is the reaction quotient. It is a measure of the progress of a chemical reaction.

The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.

At equilibrium both Kp and Q are equal. Q = Kp

If Q < Kp then the reaction will go to the right (forward reaction) trying to reach the equilibrium,

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Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.

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3 years ago