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loris [4]
3 years ago
9

Plz help me its the last question

Chemistry
1 answer:
svetoff [14.1K]3 years ago
3 0

Answer:

¹⁶⁸₇₉Au

Explanation:

The symbol of the atom is given as;

          ¹⁷²₈₁Tl

If undergoes a nuclear reaction and it ejects an alpha particle;

 An alpha particle is the same as an helium atom

      ¹⁷²₈₁Tl  →  ₂⁴H   +     ₐᵇK

K is the hypothetical symbol of the new atom

b is the new mass number

a is the new atomic number;

 Conserving mass number;

        172  = 4 + b

        b  = 172  - 4  = 168

Conserving atomic number;

        81  = 2 + a

        81 - 2  = a

         a  = 79

The new compound is gold with a symbol of;

       ¹⁶⁸₇₉Au

You might be interested in
How many neutrons does an element have if its atomic number is 41 and its mass number is 170?
BARSIC [14]

atomic number = protons.

protons+neutrons=atomic mass.

170 (mass) - 41 (proton/number) = 129

that should be ur answer. I hope this helps!

7 0
4 years ago
What is the molar mass of magnesium
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hi cut person cute picture what's up my friend

6 0
3 years ago
How much carbon dioxide is released when it is fully combusted with 4Kg of ethanol with more than enough oxygen? How do you work
Karolina [17]

Answer:

7.640 kg

Explanation:

Step 1: Write the balanced complete combustion equation for ethanol

C₂H₆O + 3 O₂ ⇒ 2 CO₂ + 3 H₂O

Step 2: Calculate the moles corresponding to 4 kg (4000 g) of C₂H₆O

The molar mass of C₂H₆O is 46.07 g/mol.

4000 g × 1 mol/46.07 g = 86.82 mol

Step 3: Calculate the moles of CO₂ released

86.82 mol C₂H₆O × 2 mol CO₂/1 mol C₂H₆O = 173.6 mol CO₂

Step 4: Calculate the mass corresponding to 173.6 moles of CO₂

The molar mass of CO₂ is 44.01 g/mol.

173.6 mol × 44.01 g/mol = 7640 g = 7.640 kg

5 0
3 years ago
What’s the symbol of the element that has 8 protons, 9 neutrons, and 8 electrons
Katena32 [7]

Answer:

oxygen

Explanation:

 The given isotope has 8 protons and 8 electrons, so the atomic number of the given isotope is 8, which is the atomic number of oxygen.

7 0
3 years ago
What is the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol)?
NemiM [27]

the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g

The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn

3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2

the formula is n= mass/M so, now substituting values

m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3

so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g

so mass of aluminum oxide obtained = 1.36g

To learn more about Mass:

brainly.com/question/19694949

#SPJ4

3 0
2 years ago
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