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nydimaria [60]
3 years ago
12

PLEASE ANSWER NOW!!!!! WILL GIVE BRAINLIEST!!!

Chemistry
1 answer:
oee [108]3 years ago
5 0

Answer:

a

b

Explanation:

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Please respond guys I’ll give brainliest and 100 points
Contact [7]

Answer:

Name

Atomic Number

Atomic Symbol

Atomic Weight

Phase

Color

Classification

Group in Periodic Table

Group Name

Period in Periodic Table

Block in Periodic Table

Electronic Configuration

Melting Point

Boiling Point

Electronic Shell Structure

CAS Number

Neighborhood Elements

Lithium

3

Li

6.941

Solid

Silver

alkali metal

1

lithium family  

2

s

[He] 2s1

180.54 °C

1342 °C

2, 1

CAS7439-93-2

Neighborhood Elements of Lithium

Cesium

55

Cs

132.90545

Solid

Silver

alkali metal

1

lithium family  

6

s

[Xe] 6s1

28.44 °C

671 °C

2, 8, 18, 18, 8, 1

CAS7440-46-2

Neighborhood Elements of Cesium

Explanation:

4 0
3 years ago
Brainliest grind of 2014i-
aksik [14]

Answer:

IM just too pogchamp

Explanation:

5 0
3 years ago
Fe2O3 + CO --> Fe + CO2
satela [25.4K]

Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

                       Fe₂O₃   + 3CO    ⇒  2Fe  +   3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g

CO = 12 + 16 = 28 g

2.- Calculate the proportions

theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

experimental proportion Fe₂O₃ / CO = 400/224 = 1.78

As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.-     160 g of Fe₂O₃  --------------- 2(56) g of Fe

         400 g of Fe₂O₃ ---------------  x

         x = (400 x 112) / 160

        x = 280 g of Fe

4.-      160 g of Fe₂O₃  --------------- 3(44) g of CO₂

          400 g of Fe₂O₃  --------------  x

          x = (400 x 132)/160

         x = 330 gr

3 0
3 years ago
N2+3H2 forms 2NH3
Nookie1986 [14]

ok ther only one solution n2 is ÷ 2h×2 is ok but the problem is that the standard form of the square is not yet

4 0
2 years ago
H 2(g)+I 2(g)→2 H I(g)
dlinn [17]

Answer:

The images for the 3 sub-questions have been presented in the first, second and third attached image to this solution.

Explanation:

The reaction for the reaction between Hydrogen gas and Iodine to give Hydrogen iodide

H₂ (g) + I₂ (g) → 2 H I(g)

ΔH∘rxn = −9.5 kJ/mol r x n

a) From the information provided, the heat of reaction being negative shows that the reaction is an exothermic reaction with the products for an exothermic reaction having a lower energy content/level as the reactants for this reaction.

This shows that the energy diagram will have the products at a lower level than fe reactants.

The sketch of the energy diagram for this exothermic reaction is presented in the first attached image to this solution.

The heat of reaction is shown on the energy diagram, together with the activation energy, Ea, the heat content/energy level for the reactants (Hr) & products (Hr) and finally the ΔH∘rxn.

ΔH∘rxn = Hp - Hr

b) When a catalyst that speed up a chemical reaction is introduced to the chemical reaction, the catalyst goes about making the reaction faster by lowering the activation energy of the reaction.

The activation energy is the minimum energy that the reactants must possess to the able to form products. On the graph, it is denoted as Ea, the difference in energy between the peak of the curve and the emergy level of the reactants.

So, a catalyst will cause this activation energy to be lowered to a new level of Ea₁.

The energy diagram of this is presented in the second attached image to this answer.

The ΔH∘rxn remains unchanged for this introduction of catalyst.

The broken lines are used to represent the lowered activation energy action of the catalyst.

c) The reverse reaction will have opposite the energy properties of the initial reaction.

The initially exothermic reaction with higher heat content of reactants than products is now an endothermic reaction with heat content/energy level of the products higher than that of the reactants.

The energy diagram is presented in the third attached image.

The activation energy is bigger and the ΔH∘rxn is now positive and equal to 9.5 kJ/mol, the direct additive inverse of the ΔH∘rxn for the initial exothermic reaction.

Hope this Helps!!!

7 0
3 years ago
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