Question

Drag and drop a statement or reason to each box to correctly complete the proof. Statement Reason NQ ⎯ ⎯ ⎯ ⎯ ⎯ ⎯ N Q ¯ is an altitude of △MNP △ M N P . Given ∠NQM ∠ N Q M and ∠NQP ∠ N Q P are right angles. Definition of altitude △NQM △ N Q M and △NQP △ N Q P are right triangles. Definition of sine ratio psinM=h p sin M = h and msinP=h m sin P = h Multiplication Property of Equality psinM=msinP p sin M = m sin P psinM pm = msinP pm p sin M p m = m sin P p m sinM m = sinP p sin M m = sin P p Simplify. In △HJK △ H J K , m∠H= 52 ∘ m ∠ H = 52 ∘ , m∠K= 73 ∘ m ∠ K = 73 ∘ , and JK=14 yards J K = 14 yards . What is HK H K ? Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth. yd Assessment navigation

Answer 1

Answer: next time I encouage the use of use a trig calculator - or look it up on khan adademy, specificly trig sine cosine and tangent. plz and thankyou, HK=14.553---

Step-by-step explanation:

aside from the fact that this is multiple questions i will awnser the second wich is about triange "HJK" its actualy really easy -use a trig clalculator I like this one https://www.calculator.net/triangle-calculator.html?vc=52&vx=&vy=&va=&vz=14&vb=73&angleunits=d&x=62&y=28 ---but its your choice otherwise look up sin cos and tan on khan academy, wich is free. but for now i beleive this is what you need, i inserted the image subsitute the abc values for hjk and you got all the stats!  (khan gives a better explanation than me on this!