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3 years ago

Can someone help me find my error

Mathematics

1 answer:

AfilCa [17]3 years ago

6 0

Answer:

try dividing 102 by 4 then after that make the length a lil bit bigger than the width but make sure it still equals 102

Step-by-step explanation:

mark me brainleist and ill give solution

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Which is the equation of a line that has a slope of 2 and contains the point (0,5)

riadik2000 [5.3K]

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=2(x-0) \\\\\\ y-5=2x\implies y=2x+5$

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3 years ago

Which expressions are equivalent to − 56 z + 28 −56z+28minus, 56, z, plus, 28? Choose 2 answers: Choose 2 answers: (Choice A) A

Dmitrij [34]

Answer:

$(D)-2(28z-14) \: and\:\\(E) -7(8z-4)$

Step-by-step explanation:

We are to determine which of these expressions are equivalent to: $-56 z + 28$

$(A)\frac{1}{2}\cdot(-28z+14) \\(B)(-1.4z+0.7)40\\(C)(14-7z)\cdot(-4)\\(D)(8z-4)(-7)\\(E)-2(-28z-14)$

$-56 z + 28$

If we factor out -2

$-56 z + 28=-2(\frac{ -56 z}{-2} + \frac{28}{-2})=-2(28z-14)$

If we factor out -7

$-56 z + 28=-7(\frac{ -56 z}{-7} + \frac{28}{-7})=-7(8z-4)$

Therefore, the two equivalent expressions are:

$-2(28z-14) \: and\: -7(8z-4)$

5 0

2 years ago

1. Find m

Bess [88]

It's forming a circle so we know that together it's going to add up to 360. #1 is 66 because angle A trough E is straight and we have 90 on angle ACF and it's vertical to angle FCG. #2 is 125 because angle ACB is 24 because it's vertical to angle GCE. #3 is 114 because 90 and 24 is 114. #4 is 156 because 66 and 90 equal 156.
1. FCG = 66
2. BCD = 125
3. FCB = 114
4. ACG = 156

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3 years ago

HIGH SCHOOL

-BARSIC- [3]

Answer:99.9

Step-by-step explanation:

6 0

3 years ago

Here's another Math one worth 10.

tia_tia [17]

<span>In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
The short leg is </span>the side opposite the 30 degree angle. If the short leg =x, then the hypotenuse = 2x

The ratio of the short leg to the hypotenuse in the given triangle is cos(60°)

$
cos(60^o) = \frac{adjacent \ side}{hypotenuse } = \frac{x}{2x} = \frac{1}{2}$

Answer is C. 1:2

7 0

2 years ago