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3 years ago

5

Find the value of x.

1 answer:

blagie [28]3 years ago

4 0

Answer:

Step-by-step explanation:

Ask yo teacher for help bih

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Directions: Use a proportion to solve the problem.

spin [16.1K]

So, since she weights 6 times more on earth, say for every lb on the moon is 6lbs on earth then.

now, if 1lb on the moon is 6lbs on earth, how much is 90 earth lbs on the moon?

$\bf \begin{array}{ccll}
moon&earth\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&6\\
m&90
\end{array}\implies \cfrac{1}{m}=\cfrac{6}{90}\implies \cfrac{1\cdot 90}{6}=m$

5 0

4 years ago

Please help I need you

mario62 [17]

Answer:

The answer is B.

Step-by-step explanation:

Diameter x Pi = Circumference

8 x 3.14 = 25.12

8 0

3 years ago

Read 2 more answers

IM STCK PLZ HELP!!! THANK YOU :)

lesya [120]

Answer:

x = 81, y = 68 and z = 99

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

z is an exterior angle, thus

z = 63 + 36 = 99

x and z form a straight angle and are supplementary, so

x + z = 180, that is

x + 99 = 180 ( subtract 99 from both sides )

x = 81

The sum of the 3 angles in a triangle = 180°, thus

z + y + 13 = 180, that is

99 + y + 13 = 180

112 + y = 180 ( subtract 112 from both sides )

y = 68

7 0

3 years ago

Who spent more of their allowed on pizza? 2/5 and 0.25

zheka24 [161]

Answer:

2/5, because 2/5 is bigger than 0.25.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Whats the roots of the following three problems:

klemol [59]

QUESTION 1

The given function is

$f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}$

We simplify to get;

$f(x)=\frac{x-3}{x+2}$

This function is equal to zero when $x-3=0$

$\Rightarrow x=3$

QUESTION 2

The given function is

$f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}$

$f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}$

We factor to get;

$f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}$

$f(x)=\frac{5(x-1)}{(2x-3)}$

This function equals zero when

$5(x-1)=0$

$x=1$

QUESTION 3

The given function is

$f(x)=\frac{x^3-8}{x^2-6x+8}$

We factor to get,

$f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}$

$f(x)=\frac{x^2+2x+4}{x+4}$

The function equals zero when $x^2+2x+4=0$

$D=b^2-4ac$

$D=2^2-4(1)(4)$

$D=-12$

Hence the equation has no real roots.

The complex roots are

$x=-\sqrt{3}i-1$ or $x=-1+\sqrt{3}i$

4 0

3 years ago