Find the matrices of the following linear transformations
1 answer:
Answer:
The matrixes are in the explanation box.
1. A mapping of (x,y,z) to (x,y,0)
2. Is a mapping of (x,y,z) to (-x,-y,z)
Step-by-step explanation:
We have the orthogonal projection onto the cy-plane to be a mapping of (x,y,z) to (x,y,0). Then we will have a transformation matrix that has the form below.
[1 0 0]
[0 1 0]
[0 0 1]
For the reflection in the z-axis,it is a reflection of (x,y,z) to (-x,-y,z). Our matrix will then have the form below
[-1 0 0]
[0 -1 0]
[0 0 1]
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Answer:
B.
Step-by-step explanation:
Well slope-intercept form is .
Let's start with the slope.
In this case, finding the slope is easy.
It should have a negative slope.
So we can cross out answer choices A. and C.
Also, we can cross out D. because it just makes no sense, -10/3, if you start from the y-intercept and go down 10 and across 3, yeah that's
not the slope.
So we can cross out D.
The only answer choice left is B.
We can tell the y-intercept is 1/2 because like come on so B is the correct answer.
B.
In the case above, the length of Angle DA is 6 and angle ABD ≈ Angle CAD.
<h3>What is the angle about?</h3>Note that:
Δ ABC , A = 90
To find length of DA :
Let Δ ACB = x
So Δ ABC = 90 -x
For Δ ABC and ADC:
Δ ADB = Δ ADC (90°)
Δ ABD = Δ DAC (90 - x)
For Δ ABC ≈ ADC:
AD² = BD. CD.
AD²= 9 . 4
AD²= 36
AD = 6
Therefore, In the case above, the length of Angle DA is 6 and angle ABD ≈ Angle CAD.
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