Answer:
Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
Step-by-step explanation:
Feets of fencing = 14
Perimeter = 14
Let x = Length y = width
Perimeter = 2(x + y)
For x = 1
2(1 + y) = 14
1 + y = 7
y =6
Area of rectangle ; x *y = 1 * 6 = 6 ft²
For x = 2
2(2 + y) = 14
2 + y = 7
y = 5
Area of rectangle ; x *y = 2 * 5 = 10 ft²
For x = 3
2(3 + y) = 14
3 + y = 7
y =4
Area of rectangle ; x *y = 3 * 4 = 12 ft²
For x = 4
2(1 + y) = 14
4 + y = 7
y = 3
Area of rectangle ; x *y = 4 * 3 =12 ft²
Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
All of them could be as A would be an equilateral B,C,D would be irregular triangles and 3 would be an Isosceles triangle but if you had to go with one it would be A
d₁ = -16t² + 122t
d₂ = -16t² + 84t
d = d₁ - d₂
d = -16t² + 122t - (-16t² + 84t)
d = 38t
After five seconds, t=5,
d = 38(5) = 190
Answer: 190 feet
9^2/9^7
when dividing powers, we subtract the exponents
9^(2-7)
9^ (-5)
a negative exponent flips from the numerator to the denominator
1/ 9^5
Choice D
0.019 is the correct answer. I hope this is the answer you are looking for! :)
