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Anika [276]
3 years ago
11

Mary went to the park with Amy at 2:30 pm. They played for 1 hour 30 min. At what time did the finish playing? Give your answer

in 24-hour clock format and also draw the clock.
Mathematics
2 answers:
puteri [66]3 years ago
6 0

Answer:

4:00 pm

Step-by-step explanation:

deff fn [24]3 years ago
3 0

Answer:

4:00

Step-by-step explanation

First, we add the minutes. 30 + 30 is 60. One hour is 60 minutes so we add 1 when we are adding the hours. 2 + 1 + 1 = 4 so it is 4:00 when they finished playing. I cannot draw the clock because it is not letting me do so.

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Step-by-step explanation:

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
A volume of the cone is (1/3) the volume of a cylinder. The volume of the sphere is what fraction of the volume of the cylinder?
xenn [34]

Answer:

4/3

Step-by-step explanation:

To know this, let's write down the formulas for the volume of cylinder and sphere.

Vs = 4/3πr³   (1)

Vc = π r² h    (2)

Now, we do have a little problem here and its the fact that the sphere do not have a height like the cylinder do. But in this case so if you want to have an idea of the fraction of the volume, we will assume that the cylinder has the same height as its radius. Assuming this we have the following:

Vs / Vc = 4πr³ / 3πr²h

Vs/Vc = 4πr³ / 3πr³

From here, we can cancel out the values of π and r³:

Vs/Vc = 4/3

<h2>Vs = 4/3 Vc</h2>

Thus we can conclude that the volume of the sphere is 4/3 the volume of a cylinder.

Hope this helps

8 0
3 years ago
Please help.
ryzh [129]

Answer:

E and D

Step-by-step explanation:

3 0
3 years ago
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