I think a) would be the answer. I proceeded by elimination: the domaine of the function goes from 3 and continues to infinity, so that leaves with a) and b) as possible answers. Both have the same range and both of their functions reflect over the x axis, so we have to compare the two answer by looking at the position of the function in the graph. The function is in the first quadrant (top right corner), so the position of the function has to be at our right, which leads us to a).
Answer: <u>30</u>
Step-by-step explanation:
Yvette- <em>100-7</em>
Isandro- <em>0+3</em>
1.) I'm going to speed up the process and multiply by 5.
Yvette: <em>100-7</em>
7 × 5 = 35
100-35= 65
65-35= 30
Isandro: <em>0+3 </em>
3 × 5 = 15
0+15= 15
15+15=<em> </em>30
2.) If they keep going on this pattern they will have the same number on the 10 round.
Answer:
80 ounces
Step-by-step explanation:
In one pint, there is 16 ounces. Thus, if she picked five pints, 16 × 5 = 80 ounces.
Another way to solve this problem is by setting a proportion.
Therefore, the answer is 80 ounces.
Y - 8 =(-8/9)(x - 3)
y - 24/3 = (-8/9)x + 8/3
y = (-8/9)x + 32/3
Well, first of all, the first statement (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent. That's no big deal, and it's no help in answering the
question.
The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.
Then, when you multiply (length x width) to get the area, you'd have
Area = (2 x original length) x (2 x original width)
and that's
the same as (2 x 2) x (original length x original width)
= (4) x (original area) .
Here's an easy, useful factoid to memorize:
-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by x¹
-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by x²
-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by x³
And that's all the dimensions we have in our world.
_______________________________
Oh, BTW . . .
-- Dilate a point (0 dimensions) by 'x' . . . multiply it by x⁰ (1)
