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2 years ago

13

On a road trip, london and his friends see 10 cities over 5 days. How many cities Landon and his friends will see in 8 days? Sol

ve using unit rates. HELP ME

1 answer:

Svetlanka [38]2 years ago

6 0

Answer:

16 cities

Step-by-step explanation:

if 5days = 10 cities

8days=?

applying cross multiplication :

(8days × ten cities )÷5 day

= 16 cities

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Selena earned $200 last month babysitting. She used 25 of her earnings to buy a video game. How much did she spend on the video

babymother [125]

Answer:

See below

Step-by-step explanation:

<u>Is that $25 or 35%?</u>

If $25, she spent $25.

If 25%, she spent (0.25)*(200) = $50.

3 0

2 years ago

\sqrt{12} real number whole number integer rational number

Sladkaya [172]

$\sqrt{12}$ is an irrational number

7 0

2 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

You can represent the measures of an angle and its complement as x °and (90 - x). Similarly, you can

Tanzania [10]

Answer:

33°
90° -J°

Step-by-step explanation:

<h3>1)</h3>

If x represents the measure of the angle, its complement is 90-x. The problem statement tells us ...

x +24 = 90 -x

2x = 66 . . . . . add x-24

x = 33 . . . . . . divide by 2

The measure of the angle is 33°.

__

<h3>2)</h3>

Using J for x in the given complement relation:

The measure of the complement of J° is (90 -J)°.

5 0

2 years ago

What is greater 3 x 1/10 plus 4 x 1/100 plus 8x 1/1000 greater than one and two tenths

Elena L [17]

So, first let's change these numbers into decimal form:
3*0.1 + 4*0.01 + 8*0.001 ? 1.2
Multiply:
0.3 + 0.04 + 0.008 ? 1.2
0.348 < 1.2
One and two tenths is larger.
Hopefully this is what you're asking, as this question is unclear

5 0

2 years ago

Read 2 more answers