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Mnenie [13.5K]
3 years ago
13

What is the least common multiple of 2, 6, and 15?

Mathematics
1 answer:
VLD [36.1K]3 years ago
5 0

Answer:

30

Step-by-step explanation:

Prime factorization of the numbers:

2 = 2 × 1

6 = 2 × 3

15 = 3 × 5

LCM(2, 6, 15)

= 2 × 3 × 5

= 30

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Plz help. My brain is melted.
AlexFokin [52]

Answer:

The answer is 4.

Step-by-step explanation:

if you havent figured that our already.

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8 0
3 years ago
Can someone find rate of change of y pls ( irrelevant answers and links will be reported)
Alja [10]

Answer:

Step-by-step explanation:

As x increasess by 5 units from 0 to 5, y increases by 6,250 to -30,000.

The rate of change is:

  change in y            6250

---------------------- = ------------------- = 1250 (units of x) / (units of x)

  change in x                 5

7 0
3 years ago
Read 2 more answers
she has 2 1/2 cups of peanuts. 3 1/4 cups of rainsins and 2 2/3 cups of banana chips. how many cups of trail mix can she make
andriy [413]

Answer:

8 cups of trail mix

Step-by-step explanation:

2 1/2 + 3 1/4 + 2 2/3= 8 5/12

6 0
4 years ago
Read 2 more answers
Jethro used dimensional analysis to convert one rate of speed to another. Two of the conversion factors he used are 5280 ft/1 mi
NNADVOKAT [17]

The units of the initial and final rates of speed are;

<u><em>Initial rate of Speed = ft/hr</em></u>

<u><em>Final rate of speed = mi/min</em></u>

  • We are told that the conversion factors he used are;

5280 ft/1 mi and 1 hr/60 min

  • Now, the meaning of 5280 ft/1 mi denotes that;

5280 ft mile is equivalent to 1 mile

This means that the initial distance <em>unit </em>used was ft while the final one was mile

Also, 1 hr/60 min denotes that;

1 hour is equivalent to 60 minutes.

This means that the initial time units used was hour while the final one was minute.

  • In conclusion, since we know the initial time and distance units used, we can say that the initial rate of speed ft/hr while final speed rate was miles/minutes.

Read more at; brainly.com/question/17734333

3 0
3 years ago
Please help with problem
siniylev [52]
5.
that is square-kite

square=AC^2=(AE+EC)^2=(9+15)^2=24^2=576

kite=1/2 times diagonals=1/2 times AC times BD=1/2 times 24 times (BE+ED)=12 times (7+7)=12 times 14=168

so the shaded area=576-168=408 square inches





6.
trapezoid=(base1+base2) times 1/2 times height

big one is base1=14, base2=25
height =10+12=22
area=(1/2)(14+24)(22)=(11)(38)=418

small one is base1=8
base2=25
height is 10
area=(1/2)(25+10)(10)=(5)(35)=175
so shaded area is 418-175=243 square cm
5 0
4 years ago
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