1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ad-work [718]
2 years ago
5

Pls help me its also easy

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

C

Step-by-step explanation:

Ferdinand's equipment is higher than Rachel's equipment.

You might be interested in
Fiona wrote the linear equation y = x – 5. when henry wrote his equation, they discovered that his equation had all the same sol
djverab [1.8K]
I would go with A but I am not 100% sure so you may want to check however you can.
6 0
3 years ago
Read 2 more answers
Evaluate the expression when x = 6<br> 3x - 1
kari74 [83]

Answer:

17

Step-by-step explanation:

3x - 1; x = 6

3x - 1

3(6) - 1

18 - 1 = 17

<u>-TheUnknown</u><u>S</u><u>cientist</u>

7 0
3 years ago
Explain how finding the square root of a number is different from finding the cube root
sasho [114]
U could searc9 it up and it will help u
7 0
3 years ago
Halle solved 664/48 below. She got a quotient of 13 with a remainder of 40. How could she solve 659/48 without redoing the work?
Lerok [7]
She should multiply the quotient by 48.
3 0
3 years ago
Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

6 0
3 years ago
Other questions:
  • PLEASE HELP NEED ANSWER NOWThree salesmen work for the same company, selling the same product. And, although they are all paid o
    15·1 answer
  • ∠RQT is a straight angle. What are m∠RQS and m∠TQS?
    13·1 answer
  • Max spends three times as long on his math homework than he does on his science homework. If he spent total of 64 minutes on mat
    5·1 answer
  • If the blue radius below is perpendicular to the chord AC, which is 6 units long, what is the length of the segment AB?
    6·1 answer
  • Tor given terms. Find how much the account needs to hold to make this possible. Round your answer to the nearest dollar. Regular
    8·1 answer
  • HELPPPPPP ANSWER ASAP
    9·2 answers
  • Helpppp Asapppp I’m timed
    10·1 answer
  • Is the value 5 a solution to the inequality r + 4 &lt; 7 ?
    6·2 answers
  • Find the measures of the interior angles of the triangle.
    14·2 answers
  • 2x^3-x^2+x-2 factorize​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!