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frozen [14]
3 years ago
12

Which set of measurements could make a triangle?

Mathematics
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

3.) a. 9mm b. 10mm c. 8mm

Step-by-step explanation:

All you have to do is use the Triangle Inequality Theorem, which states that the sum of two side lengths of a triangle is always greater than the third side. If this is true for all three combinations of added side lengths, then you will have a triangle.

Formula:

a + b = (answer) > c

a + c = (answer) > b

b + c = (answer) > a

try to solve it yourself so you can do it on your own in the future.

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What is 2/100000 as a decimal
blsea [12.9K]
2.0e-6
Is the answer to your question

6 0
4 years ago
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1 3/5 + 2/3=?????????????????????
melomori [17]

Answer:

2.26666666667 is the answer

4 0
3 years ago
Why is (x-3) NOT a factor of x3+2x2-5x-6
ivolga24 [154]

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Step-by-step explanation:

Given expression is:

x^3+2x^2-5x-6

We have to check if x-3 is a factor of given expression

In order for x-3 to be a factor of expression, we have to put x-3 = 0 => x=3 in expression.

If the expression is zero at x=3 then x-3 is a factor of expression otherwise not.

So putting x=333 in expression

=(3)^3+2(3)^2-5(3)-6\\= 27+2(9) - 15-6\\= 27+18-15-6\\= 45-21\\=24 \neq 0

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/4228574
  • brainly.com/question/4279146

#LearnwithBrainly

8 0
3 years ago
Please answer this question :)
sveticcg [70]

Answer:

a)  49.41

b) not quite sure

Step-by-step explanation:

sorry

6 0
3 years ago
The radius of a circular plate is 7 inches.
Readme [11.4K]

Answer:

153.94 in²

Step-by-step explanation:

The equation for Area is

Area = πr²

Plugging in the value for the radius into r, it will be

(note, r means radius)

Area = π(7)²= 49π ≈ 153.94

The units is -> in² so add that in the end

5 0
3 years ago
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