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3 years ago

X^9/7 convert from exponent form to radical form

Mathematics

1 answer:

Wittaler [7]3 years ago

4 0

Answer:

$x^{\frac{9}{7}} = \sqrt[7]{x^9}$

Step-by-step explanation:

You can solve this by realising that the denominator of a fractional exponent can be expressed as the base of a radical.

Note also that the order does not matter. You could also express it as

$\sqrt[7]{x}^9$

The reason this works is that you're effectively breaking the exponent into fractions. The first answer is the equivalent of:

$(x^9)^{1/7}$

and the second would be:

$(x^{1/7})^9$

In both cases, the exponents would be multiplied, giving the same result.

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Bill earns 12$ per hr

garik1379 [7]

Answer:

dang nice

Step-by-step explanation:

3 0

3 years ago

Maggie buys 5 apples and 4 oranges for $10 and Lynn buys 5 apples and 5 oranges for $11. What is the price for an apple and what

nlexa [21]

Make 2 eqn, let a be apples and o be oranges:

1. 5a + 4o = 10
2. 5a + 5o = 11

set up an elimination:
1. minus 2.
5a + 4o = 10
- 5a + 5o = 11
____________
o = 1

sub “o” into one of the eqn

5a + 5(1) = 11
5a = 11-5
5a = 6
a = 6/5
a = 1.2

therefore, an orange costs $1.00 and an apple costs $1.20

6 0

4 years ago

The school cafeteria surveyed students to see what their favorite lunch is, and the

Sergio039 [100]

Answer:

40%

Step-by-step explanation:

Degree representing students who prefer burgers = 144°

Percentage of students who like burger = $\frac{144}{360} \times 100$

$= 0.4 \times 100$

$= 40 percent$

Percentage of students who offered burger = 40%

3 0

3 years ago

Which phrase best describes the translation from the graph y=(x-5)^2+7 to the graph of y=(x+1)^2-2

Helga [31]

Start from the parent function $f(x)=x^2$

In the first case, you are computing

$f(x-5)+7$

In the second case, you are computing

$f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)$ , you translate the function horizontally, $k$ units left if $k>0$ and $k$ units right if $k$ .

On the other hand, when you transform $f(x) \to f(x)+k$ , you translate the function vertically, $k$ units up if $k>0$ and $k$ units down if $k$ .

So, the first function is the "original" parabola $f(x)=x^2$ , translated $5$ units right and $7$ units up. Likewise, the second function is the "original" parabola $f(x)=x^2$ , translated $1$ units left and $2$ units down.