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2 years ago

What are the equivalent fractions for 2 1/5 and 1 5/6 using 30 as the common denominator

Mathematics

1 answer:

Anuta_ua [19.1K]2 years ago

4 0

Answer:

2 6/30 and 1 25/30

Step-by-step explanation:

First, you need to find 30÷5 and 30÷6. You do this because you need to know the multiplier when you create an equivalent fraction. 30÷5 is 6 and 30÷6 is 5. 2 1/5. You need to multiply the 1 and 5 by 6, that is 2 6/30. 1 5/6. 5 and 6 multiplied by 5 is 25 and 30. 1 5/6=1 25/30

You might be interested in

100% is 75 oranges what percent is 250 oranges?

Whitepunk [10]

Answer:

x=333.33%

Step-by-step explanation:

hello

you can resolve this by using the rule of 3,let´s see

75 oranges =100%

250 oranges = x%?

75 oranges* x%=250 oranges *100%

$x=\frac{250*100}{75}$

x=333.33%

Have a great day.

4 0

3 years ago

Identify the variation as direct, inverse, joint or combined. A = πr^2

Reika [66]

Answer:

1. y = 7x. This is an example of direct variation as the value of y also increases if the value of x is increased.

2. xy = 24. This is an example of inverse because the value of y is decreased when x is increased.

3. F = 4/R. This is inverse variation for the same reason as number 2.

4. m/n = 4. Direct variation. For the same reason as number 1.

5. i = 2pr. Joint variation. The value of i is dependent on the values of two other variables.

6. R = cl/r². Joint variation.

7. A = pir². Direct variation. I believe pi here is for π, leaving only A being dependent only to value of r.

8. V= pir²h. Joint variation.

Step-by-step explanation:

7 0

3 years ago

The amount of money A accrued at the end of

Rudiy27

B is the answer no capppppp

7 0

2 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

Find the slope of the line that passes through the points (1,-5) and (5. 7).

SCORPION-xisa [38]

Answer:

y= 5.7x-10.7

Step-by-step explanation:

the formula is y=mx+b

4 0

3 years ago

Read 2 more answers