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Amiraneli [1.4K]
3 years ago
10

Can someone help me with this ASAP please I’m being timed !

Mathematics
1 answer:
viva [34]3 years ago
7 0

Answer:

%65

Step-by-step explanation:

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Step-by-step explanation:

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Fill in the next entry in the pattern<br> 81, 27, 9, 3,
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The answer to your problem is 1
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Read 2 more answers
A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te
garri49 [273]

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

  • A one tailed test is a test that have hypothesis of the form

H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu

  • A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
  • Rejection region is the area for which the null hypothesis is rejected.
  • If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.
  • If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

6 0
3 years ago
PLEASE HELPPPPP. URGEENNTT!!! I DONT KNOW HOW TO SOLVE THIS
Oksi-84 [34.3K]

Answer:

A = 58.7 degrees

B = 66.9 degrees

C = 34.1 degrees

Step-by-step explanation:

<u><em>For <A:</em></u>

Tan A = \frac{opposite}{adjacent}

Tan A = \frac{23}{14}

Tan A = 1.6

A = Tan^{-1} 1.6

A = 58.7 degrees

<u>For <B:</u>

Sin B = \frac{opposite}{hypotenuse}

Sin B = \frac{23}{25}

Sin B = 0.92

B = Sin^{-1} 0.92

B = 66.9 degrees

<em><u>For <C:</u></em>

Sin C = \frac{opposite}{hypotenuse}

Sin C = \frac{14}{25}

Sin C = 0.56

C = Sin^{-1}0.56

C = 34.1 degrees

6 0
3 years ago
Jake's final grade in his science class is calculated by finding the mean of his scores for six project reports. The score Jake
Yanka [14]
Let lowest possible score be x (66+ 80+ 88+ 82 +72+ x)/6=80 on solving we get ans as 92
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3 years ago
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