All categories

3 years ago

Which angles are supplementary to 1 ( Select all that apply)?

Mathematics

2 answers:

bagirrra123 [75]3 years ago

7 0

<h3>2 Answers: Angle 4 and angle 2</h3>

==================================================

Explanation:

Supplementary angles add to 180 degrees. Visually, supplementary angles can be glued together to form a straight angle or a straight line.

We see that happens with angles 1 and 4, and this also happens with angles 1 and 2. This is why these two angles make up the answer.

--------------

The other answer choices can be ruled out.

Angles 1 and 9 would be congruent if we knew the shallow sloping lines were parallel. The only time angles 1 and 9 are supplementary is if both are 90 degrees. In any other case, they are not supplementary angles.

Angles 1 and 12 are same side exterior angles. They would be supplementary if the shallow sloping lines were parallel. However, if you extend out each line, you'll see that they eventually intersect. Parallel lines never intersect.

vova2212 [387]3 years ago

3 0

There are two answers to this question and it is 4 and 2

You might be interested in

What are the points of intersection of -x^2+9x-3 and y=3x

ELEN [110]

Answer:

Easiest and fastest way is to graph both equations into a graphing calc and trace the graph to where they intersect.

Alternatively, you can use substitution to solve for your answer.

Step-by-step explanation:

8 0

3 years ago

What is 1-2sin^2x=sinx <br> Please show steps and find all solutions in interval [0,2pi)

Svetlanka [38]

Answer:

$\large\boxed{x=\dfrac{3\pi}{2}\ \vee\ x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}}$

Step-by-step explanation:

$1-2\sin^2x=\sin x\\\\\text{substitute}\ t=\sin x,\ t\in[-1,\ 1]\\\\1-2t^2=t\qquad\text{subtract t from both sides}\\\\-2t^2-t+1=0\qquad\text{change the signs}\\\\2t^2+t-1=0\\\\2t^2+2t-t-1=0\\\\2t(t+1)-1(t+1)=0\\\\(t+1)(2t-1)=0\iff t+1=0\ \vee\ 2t-1=0\\\\t+1=0\qquad\text{subtract 1 from both sides}\\\boxed{t=-1}\\\\2t-1=0\qquad\text{add 1 to both sides}\\2t=1\qquad\text{divide both sides by 2}\\\boxed{t=\dfrac{1}{2}}$

$\sin x=-1\to x=-\dfrac{\pi}{2}+2k\pi,\ k\in\mathbb{Z}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}\\\\x\in[0,\ 2\pi)$

$x=-\dfrac{\pi}{2}\notin[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+2\pi=\dfrac{3\pi}{2}\in[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+4\pi=\dfrac{7\pi}{2}\notin[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}+2\pi=\dfrac{13\pi}{6}\notin[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}+2\pi=\dfrac{17\pi}{6}\notin[0,\ 2\pi)$

4 0

3 years ago

What is the image of (2,3)(2,3) after a reflection over the line y=-xy=−x?

otez555 [7]

Answer:

After the reflection over the line y = -x, the image of the point is: (-3,-2)

Step-by-step explanation:

When a given point is reflected over a line the point only changes place but the distance between the point and the line remains same.

Let (x,y) be a point on the plane

and

y = -x be a line on the plane

When a point is reflected over a line y = -x , the coordinates of the point are exchanged which means x becomes y and y becomes x and both are negated

So (x,y) will become (-y,-x)

Given point is:

(2,3)

After the reflection over the line y = -x, the image of the point is: (-3,-2)

4 0

3 years ago

Examine the following system of inequalities.

lubasha [3.4K]

Answer:

Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)

Step-by-step explanation:

we have

$y > -x+4$ ----> inequality A

The solution of the inequality A is the shaded area above the dotted line $y=-x+4$

The dotted line passes through the points (0,4) and (4,0) (y and x-intercepts)

and

$y \leq -(1/2)^{x} +6$ -----> inequality B

The solution of the inequality B is the shaded area above the solid line $y=-(1/2)^{x} +6$

The solid line passes through the points (0,5) and (-2,2)

therefore

The solution of the system of inequalities is the shaded area between the dotted line and the solid line

see the attached figure

Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)