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Bas_tet [7]
3 years ago
10

when you divide both sides of any inequality by a negative number, you need to ___ the inequality symbol

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

when you divide both sides of any inequality by a negative number, you need to greater than the inequality symbol

Step-by-step explanation:

have a great day ahead :)

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Ernesto is shopping at store that is having a clearance sale. The price of everything in the store is discounted by 25%. If Earn
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$17.49 because you multiply 22 by .25 getting 5.5. You subtract that from the original 22 getting 16.5 which you then multiply by the sales tax .06. Add the tax amount to the 16.5 to get 17.49.
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3 years ago
What is x in the following equation -3(-4x-3) = 20
choli [55]

Answer:

Step-by-step explanation:

-3(-4x-3) = 20

Opening bracket

12x + 9 = 20

12x = 20 - 9

12x = 11

x = 11/12

4 0
3 years ago
Two forces, one of 45 pounds and the other 50 pounds, act on the same object. The angle between the forces is 33°. Find the magn
bearhunter [10]

Answer:

The magnitude of the resultant force is: 27.40 pounds

Step-by-step explanation:

Given

F_1 = 45

F_2 = 50

\theta = 33

Required

The magnitude of the resultant vector

To do this, we apply cosine formula

R^2 = F_1^2 + F_2^2 - 2 * F_1 * F_2 * \cos(\theta)

This gives:

R^2 = 45^2 + 50^2 - 2 * 45 * 50 * \cos(33)

R^2 = 2025+ 2500 - 4500* 0.8387

R^2 = 2025+ 2500 - 3774.15

R^2 = 750.85

Take square roots of both sides

R = \sqrt{750.85\\

R = 27.40

7 0
3 years ago
Find the value of the expression 0.5^10/0.5^7
SIZIF [17.4K]

Answer:

The solution is:

  • \frac{0.5^{10}}{0.5^7}=0.125

Step-by-step explanation:

Given the expression

0.5^{10}\div 0.5^7

Solving

\frac{0.5^{10}}{0.5^7}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

so

\frac{0.5^{10}}{0.5^7}=0.5^{10-7}

\mathrm{Subtract\:the\:numbers:}\:10-7=3

=0.5^3

=0.125        ∵ 0.5^3=0.125

Therefore, the solution is:

\frac{0.5^{10}}{0.5^7}=0.125

7 0
3 years ago
Can someone help me with #2 and #4
Juli2301 [7.4K]
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