Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
1/19 because the rings would be 1,3,4,5,6 respectively and then u add it up
Answer:
B, C
Step-by-step explanation:
The only statements that must be true are ones that describe the markings on the diagram:
NO as an angle bisector
N is the vertex of a pair of congruent angles
_____
The only other fact that must be true is that segments on the left side of the diagram are proportional to those (corresponding) on the right. (This is a property of the angle bisector.) There is nothing that says the sides must be equal, or that the triangle is isosceles.
Answer:
I would guess 40, I could be wrong.
Step-by-step explanation:
70-30=40. So it would be 40 units away from eachother.
Answer:
The answer is The function is decreasing for all real values of x
where
-1<x<4.
Step-by-step explanation:
