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klasskru [66]
3 years ago
10

Hiii help i will put brainliest!

Mathematics
2 answers:
Burka [1]3 years ago
5 0

Answer:

36 feet

Step-by-step explanation:

A=(4x+1)^{2}

P = 4(4x+1) = 16x+4

16(2)+4 = 36ft

Perimeter = 36ft

nydimaria [60]3 years ago
3 0
36 feet is the answer
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Which of the following numbers are greater than or equal to 4/7? Is it 2/5, 0.57, or 2/3. Use explanation why.
Sergeeva-Olga [200]

Answer:

2/3

Step-by-step explanation:

2/5=0.4 and 4/7=0.571428

0.57<0.571428

---------------------------

2/3=0.6667

which is greater than or equal to 4/7

5 0
3 years ago
At the theater, tickets for adults cost $4.75
shutvik [7]
X+y= 26 and 4.75x + 2.25y= 83.50

y=26-x( substitute this into second equation for y and solve for x)

4.75x + 2.25(26-x)= 83.50

4.75x + 58.5-2.25x= 83.50

x= 10

Now solve for y by substituting your answer for x

10+ y= 26

y=16

Therefore, 16 tickets were purchased for kids and 10 for adults.

7 0
3 years ago
5
Svetradugi [14.3K]

Answer:

The right answer is:

Option OB: f(1) = -9

Common difference: 7

Step-by-step explanation:

Given sequence is:

-9, -2, 5, 12,...

Here the first number is f(1)

Common Difference:

Common difference is the difference between consecutive terms of an arithmetic sequence. It is denoted by d.

In the given sequence,

f(1) = -9

f(2) = -2

f(3) = 5

d=f(2)-f(1) = -2-(-9) = -2+9 = 7\\d = f(3)-f(2) = 5-(-2) = 5+2 = 7

Hence,

The right answer is:

Option OB: f(1) = -9

Common difference: 7

7 0
3 years ago
Help with 2 show work
Wittaler [7]
A. from 67.86 all the way to the end. (67.86 is not filled)
b. $67.86,
    $80.00,
    $70.00(values equal to or greater than $67.86.)
c. There are many values that represent this inequality.(values equal to or greater than $67.86)

Hope this helped☺☺

8 0
3 years ago
A package of paper weighs 3\frac{4}{6} ounces. If Edward put 3\frac{1}{2} packages of paper on a scale, how much would they weig
Nadusha1986 [10]

Answer:

They would weight 1\frac{1}{21} ounces

Step-by-step explanation:

Weight of complete package of paper = 3 \frac{4}{6} ounces

Weight of complete package of paper =\frac{22}{6}ounces

Edward put3\frac{1}{2} packages of paper on a scale

So, Weight of 3\frac{1}{2} packages   = \frac{\frac{22}{6}}{3\frac{1}{2}}

Weight of 3\frac{1}{2} packages = \frac{\frac{22}{6}}{\frac{7}{2}}

Weight of 3\frac{1}{2} packages =\frac{22}{21}=1\frac{1}{21}

Hence They would weight 1\frac{1}{21} ounces

8 0
3 years ago
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