Answer:
7.92 mL
Explanation:
There is some info missing. I think this is the original question.
<em>A chemistry student weighs out 0.0617g of acetic acid (HCH₃CO₂) into a 250.mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1300 M NaOH solution.
</em>
<em>
Calculate the volume of solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.</em>
<em />
First, we will calculate the moles of acetic acid (MW 60.05 g/mol).
0.0617 g × (1 mol/60.05 g) = 1.03 × 10⁻³ mol
Let's consider the neutralization reaction between HCH₃CO₂ and NaOH.
HCH₃CO₂ + NaOH ⇄ NaCH₃CO₂ + H₂O
The molar ratio of HCH₃CO₂ to NaOH is 1:1. The moles of NaOH are 1.03 × 10⁻³ moles.
The volume of 0.1300 M NaOH that contains 1.03 × 10⁻³ mol is:
1.03 × 10⁻³ mol × 1000 mL/0.1300 mol = 7.92 mL
Answer:
Saturated = The solution cannot dissolve any more solute at a given temperature
2) Unsaturated = solution can dissolve more solute at a given temperature.
3) Supersaturated = Solution which has more solute than its saturated solution
Explanation:
<h2>
<em><u>Mark </u></em><em><u>me </u></em><em><u>brainlist</u></em></h2>
False, metamorphic rocks are formed under pressure, is crystals are then formed into layers
Answer:
wait did you tell up the answer?
Explanation:
