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xeze [42]
3 years ago
7

When this element was discovered, it exhibited luster and malleability, and it reacted very vigorously with water. This element

is never found as a free element in nature and always exists in a compound. To which group does this element most likely belong?
Chemistry
1 answer:
rjkz [21]3 years ago
5 0
The answer is potassium
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What is the name of this alkane?
Otrada [13]
It's a cyclohexane ring with an ethyl group at 1 and a methyl group at 3. The Ethyl group is bigger and more important group get's the first position.

1-ethyl-3-methylcyclohexane
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3 years ago
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1. A solution with a pH of 9 has a pOH of
Alecsey [184]

Answer:

strength = 10⁻²/10⁻³ = 10 times more acidic

Explanation:

1. A solution with a pH of 9 has a pOH of

pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5

2. Which is more acidic, a solution with a pH of 6 or a pH of 4?

pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M

3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?

soln with pH = 2 => [H⁺] = 10⁻²M

soln with pH = 3 => [H⁺] = 10⁻³M

strength = 10⁻²/10⁻³ = 10 times more acidic

4. What is the hydrogen ion concentration [H + ] in a solution that has a pH of 8?

[H⁺] = 10^-pH = 10⁻⁸M

5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)

pH + pOH = 14 => pH = 14 - 9.6 = 4.4

8 0
3 years ago
The equation below represents the overall cell reaction for an electrochemical cell that undergoes a spontaneous reaction. Fe(s)
Natalija [7]
Its b Fe(s) <span> Fe</span>2+(aq) + 2e– <span><span>       </span>E</span><span> = </span><span>+0.44 V</span>
4 0
3 years ago
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A chemist uses hot hydrogen gas to convert chromium(III) oxide to
Darya [45]

Answer: 3.024 g grams of hydrogen are needed to  convert 76 grams of chromium(III) oxide, Cr_{2}O_{3}

Explanation:

The reaction equation for given reaction is as follows.

Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O

Here, 1 mole of Cr_{2}O_{3} reacts with 3 moles of H_{2}.

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide (Cr_{2}O_{3}) is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of Cr_{2}O_{3} is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol

Now, moles of H_{2}.given by 0.5 mol of Cr_{2}O_{3} is calculated as follows.

0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}

As molar mass of H_{2} is 2.016 g/mol. Therefore, mass of H_{2} is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g

Thus, we can conclude that 3.024 g grams of hydrogen are needed to  convert 76 grams of chromium(III) oxide, Cr_{2}O_{3}.

7 0
3 years ago
Extra points!
noname [10]

Answer:

1A

2B

3B

4A

Explanation:

3 0
3 years ago
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