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GuDViN [60]
3 years ago
6

4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60

Chemistry
1 answer:
Bingel [31]3 years ago
8 0

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

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.400 moles of CO2 gas are confined in a 5.00-liter container at 25 °C. Calculate the pressure exerted in atmospheres and mm Hg.
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The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or  1486.788 mm Hg.

<h3>The ideal gas law</h3>

According to the ideal gas law, the product of the pressure and volume of a gas is a constant.

This can be mathematically expressed as:

pv = nRT

Where:

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v = volume

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R = Rydberg constant (0.08206 L•atm•mol-1K)

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In this case:

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v = 5.00 L

n = 0.400 moles

T = 25 + 273

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Now, let's make p the subject of the formula of the equation.

p = nRT/v

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Recall that: 1 atm = 760 mm Hg

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1.9563 atm = 1.9563 x 760 mm Hg

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More on the ideal gas law can be found here: brainly.com/question/28257995

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Answer:

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