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Maslowich
3 years ago
9

Jerry had k pencils. darcy and leonard then gave jerry an additional x pencils each. which expression could represent the number

of pencils jerry has now?
Mathematics
1 answer:
Rashid [163]3 years ago
6 0

Answer:

k+(x×x)

Step-by-step explanation:

k is the number of pencils jerry has, and x is the number of pencils darcy and leonard gave him EACH. So you need to multiply 'x' x2 to get the total ammount of pencils they gave him, then add 'k' to know how much in total he has now.

hope it helped! (3

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In a study of the effect of cooling rate on the hardness of welded joints, 50 welds cooled at a rate of 10°C/s had an average Ro
Studentka2010 [4]

Answer:

a) The 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

b) No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =91.1 represent the sample mean 1

\bar X_2 =90.7 represent the sample mean 2

n1=50 represent the sample 1 size  

n2=40 represent the sample 2 size  

s_1 =6.55 sample standard deviation for sample 1

s_2 =4.32 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Part a

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =91.1-90.7=0.4

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n_1 +n_2 -1=50+40-2=88  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,88)".And we see that t_{\alpha/2}=1.987  

The standard error is given by the following formula:

SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=1.325

Now we have everything in order to replace into formula (1):  

0.4-1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=-1.887  

0.4+1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=2.687  

So on this case the 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

Part b

No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

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Answer:

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Answer:

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Step-by-step explanation:

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