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2 years ago

I don’t really know how to solve these can you guys help?

Mathematics

1 answer:

Ulleksa [173]2 years ago

6 0

Answer:

So the total is 400 and then you have 4 servings

so 400/4 = 100 cal per serving

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Which of the following is equivalent to log9w

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3 years ago

Simplify expressions <br> 2a+3+a+4

Norma-Jean [14]

3a plus 7. you group the whole numbers together and than the a's. so 3+4 is 7. 2a + a is 3a.

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3 years ago

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14.4 .3 Two students are needed to work in the school store during the lunch hour every day, and four students volunteer for thi

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2 years ago

Suppose the invertible function φ(x) has the domain (−5,11) and the range (−12,1).

Rom4ik [11]

Answer:

Range of $\phi^{-1}$ is (−5,11).

Step-by-step explanation:

Given the invertible function Ф(x) which has the domain (−5,11) and the range (−12,1).

Invertible function is the function that inverses another function i.e if y=Ф(x) then x=g(y) where g is called the inverse of Ф and denoted by $\phi^{-1}$

Given Ф(x) the function whose domain is (−5,11) and range is (−12,1). Therefore, by definition of invertible function there exist a function g with domain (−12,1) and range (−5,11) which is called the inverse function denoted by $\phi^{-1}$

Hence, Range of $\phi^{-1}$ is (−5,11)

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3 years ago

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What is the value of the expression if m = –5 and n = 3? Negative StartFraction 24 Over 25 EndFraction Negative StartFraction 4

KatRina [158]

You can use the fact that a number raised to negative powers can be written as 1 divided by that number raised to positive number.

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

<h3>How can we rewrite a number raised to negative power?</h3>

Suppose we've got $a^{-b}$ . then it can be rewritten as

$a^{-b} = \dfrac{1}{a^b}$

It is because $a^0 = 1$ for any a except 0, and that $\dfrac{a^0}{a^b} = a^{0-b} = a^{-b}$

If base are same and there is multiplication, then there will be addition in power.

Also, know the fact that if base are same and there is division, there will be subtraction in power(subtracting since that denominator when goes up, its power gets negated(gets negative sign to the existing power)

Thus,

$a^b \timesa ^c = a^{b+c}\\\\\dfrac{a^b}{a^c} = a^{b-c}$

<h3>Using above method to simplify the given expression before evaluating</h3>

The given expression is $\dfrac{2m^{-1}n^5}{3m^0n^4} = \dfrac{2n^5}{3m^0m^1n^4} = \dfrac{2n^5}{3mn^4} = \dfrac{2n^{5-4}}{3m} = \dfrac{2n^1}{3m} = \dfrac{2n}{3m}$

Putting m = -5 and n=3, we get:

$\dfrac{2\times 3}{3 \times -5} = -\dfrac{2}{5}$

Thus,

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

Learn more about base and exponent(power) here:

brainly.com/question/847241

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3 years ago