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2 years ago

What is 15% of 90? A. 14.4 B. 13.5 C. 60.0 D. 16.7

Mathematics

2 answers:

Basile [38]2 years ago

6 0

Answer:

multiply 90 by 0.15. and you get 13.5

timofeeve [1]2 years ago

5 0

It's 13.5

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1x10+3×1+4×(1over1000)

Marina86 [1]

Answer:

14 and 4/1000 or 14004/1000

Step-by-step explanation:

1*10+3*1+4*(1/1000)

First i like to separate the equation by PEMDAS or order of operations. First is parentheses, which is the fraction. Then is exponents. There is none. Then multiplication and division so u solve 1*10, 3*1 and 4*1/1000.

This is the updated equation: 10+4+(4/1000)

Next you do subtraction and addition. The order does not matter if there's only addition. If there is subtraction u solve by the order of the equation. SO in this step we solve 10+4+(4/1000)

Here is the updated version: 14+(4/1000)

Then u add that which is 14 and 4/1000 or you can do 14004/1000

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2 years ago

38,477 rounded to the nearest thousand

Ganezh [65]

Answer: i'm pretty sure it's 38,500

Step-by-step explanation:

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2 years ago

Triangle ABC is shown below.

zhannawk [14.2K]

Answer:

Step-by-step explanation:

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3 years ago

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Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum

lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

$\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\$

$\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\ (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\$

$=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3} \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\$

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2 years ago

Hey I'm Chloe Can you Help Me, I will give Brainlest, Thank you :)

Mariulka [41]

Answer:

Stefan spent 108.9$ and made 12.1$

Step-by-step explanation:

Hey I'm Aiden I can help you, I will take Brainlest, Your welcome :)

take 10% of 121 and subtract it from 121 and you get the price he paid and made

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2 years ago