2 years ago

QUESTION 1

Physics

1 answer:

Molodets [167]2 years ago

3 0

Question 1: C Question 2: B, Hope this Helps!

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Two compact sources of sound oscillate in phase with a frequency of 100 Hz. At a point 5.00m from one source and 5.85 m from the

antoniya [11.8K]

Answer:

(a)1.557 radian (b) 1.424 A

Explanation:

Frequency of oscillation of sound = 100 Hz

$\Delta r=5.85-5=0.85m$

(a)The phase difference is given by $\frac{2\pi \Delta r}{λ}$ where v is the velocity of sound in air

So phase difference $\frac{2\pi \Delta rf}{v}$ as $\lambda =\frac{v}{f}$

So phase difference $=\frac{2\times 3.14\times 0.85\times 100}{343}=1.557radian$

(b) The resultant amplitude is given by $2Acos\frac{\Phi }{2}=2\times A\times cos\frac{1.557}{2}=1.424A$

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(A⃗ ×B⃗ )⋅C⃗ = 69.868

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We simplify the cross product first, thereafter the solution of the cross product is now simplified with the dot product as shown in the step by step calculation in the attachment

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